Two workers are sliding 470 kg crate across the floor. One worker pushes forward on the crate with a force of 450 N while the ot
1 answer:
Answer:
0.169
Explanation:
There are three forces acting on the crate along the horizontal direction:
- The pushing force of the first worker, F1 = 450 N forward
- The pushing force of the second worker, F2 = 330 N forward
- The frictional force acting backward
The crate slides with constant speed, so its acceleration is zero: a = 0. This means that we can write Newton's second law as
The frictional force can be rewritten as
where
is the coefficient of kinetic friction
m = 470 kg is the mass of the crate
g = 9.8 m/s^2 is the acceleration due to gravity
Substituting everything into the previous equation, we find:
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Answer:
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Explanation:
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Answer:
When the ball is held motionless above the floor, the ball possesses only GPE energy.If the ball is dropped, its GPE energy decreases as it falls.If the ball is dropped, its KE energy increases as it falls.
Explanation:
If the ball is held motionless, then its kinetic energy is equal to zero, since kinetic energy depends on the velocity. And the ball is held above the ground, which means it possesses gravitational potential energy.
If the ball is dropped, its height will decrease, therefore its gravitational potential energy will decrease. Along the way, the ball will be in free fall, and therefore its velocity will increase, hence its kinetic energy.