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juin [17]
3 years ago
11

The voltage and the current in the primary coil of a nonideal transformer are 120 volts and 2.0 amperes. The voltage and the cur

rent in the secondary coil are 19.4 volts and 11.8 amperes. What is the efficiency e of the transformer

Physics
1 answer:
Arlecino [84]3 years ago
4 0

Explanation:

Below is an attachment containing the solution.

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HELP I WILL GIVE BRAINLIEST!
Ann [662]

Answer:

Answer:B

Explanation:

Because it all stayed consistant

4 0
3 years ago
An electron that has a velocity with x component 1.6 × 106 m/s and y component 2.4 × 106 m/s moves through a uniform magnetic fi
Sergio039 [100]

Answer:

(a) 5.056 x 10^-14 N

(b) 5.056 x 10^-14 N

Explanation:

X component of velocity of electron is 1.6 × 10^6 m/s

Y component of velocity of electron is 2.4 × 10^6 m/s

X component of magnetic field is 0.025 T

Y component of magnetic field is  -0.16 T

charge on electron, q = - 1.6 x 10^-19 C

Write the velocity and magnetic field in the vector forms.

\overrightarrow{v}=1.6\times 10^{6}\widehat{i}+2.4\times 10^{6}\widehat{j}

\overrightarrow{B}=0.025\widehat{i}-0.16\widehat{j}

The force on the charge particle when it is moving in the magnetic field is given by

\overrightarrow{F}=q\left ( \overrightarrow{v}\times \overrightarrow{B} \right )

(a) Force on electron is given by

\overrightarrow{F}=-1.6\times 10^{-19}\left ( 1.6\times 10^{6}\widehat{i}+2.4\times 10^{6}\widehat{j} \right )\times \left ( 0.025\widehat{i}-0.16\widehat{j} \right )

\overrightarrow{F}=5.056\times 10^{-14}\widehat{k}

Magnitude of force is 5.056 x 10^-14 N.

(b) Force on a proton is given by

\overrightarrow{F}=1.6\times 10^{-19}\left ( 1.6\times 10^{6}\widehat{i}+2.4\times 10^{6}\widehat{j} \right )\times \left ( 0.025\widehat{i}-0.16\widehat{j} \right )

\overrightarrow{F}=-5.056\times 10^{-14}\widehat{k}

Magnitude of force is 5.056 x 10^-14 N.

Thus, the magnitude of force remains same but the direction of force is opposite to each other.

Explanation:

4 0
3 years ago
A 2 kg object has a specific heat capacity of 1,700 J/(kg \cdot⋅oC)
Nutka1998 [239]

The amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.

HOW TO CALCULATE SPECIFIC HEAT CAPACITY:

  • The amount of heat absorbed by an object can be calculated by using the following expression:

  • Q = m.c.∆T

Where;

  1. Q = amount of heat absorbed or released (J)
  2. m = mass of object
  3. c = specific heat capacity (J/g°C)
  4. ∆T = change in temperature (°C)

  • According to this question, 2 kg object has a specific heat capacity of 1,700J/kg°C and was raised from a temperature of 15 Celsius to 25 Celsius. The heat absorbed is calculated as follows:

  • Q = 2 × 1700 × {25 - 15}

  • Q = 3400 × 10

  • Q = 34000J

  • Therefore, the amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.

Learn more about how to calculate heat absorbed at: brainly.com/question/11194034?referrer=searchResults

8 0
2 years ago
A child cart is given an initial velocity of 8 m/s and undergoes a constant acceleration of 4 m/s2. Calculate the distance moved
Nesterboy [21]

Answer: This is Yazan From 10-C

Explanation

5 0
3 years ago
"List, from beginning to end, the stages in the weather as a cold front goes by: (a) warm air is forced upward where it cools; (
RSB [31]

Answer:

(a) warm air is forced upward where it cools;

(c) cumulonimbus or nimbo-stratus clouds form

(d) thunderstorms with heavy showers and gusty winds occur"

(b) air cools and sinks, pressure rises, rain stops;

Explanation:

  • A cold for front is a denser air , as that forms under the warmer and lighter air mass and this causes a low pressure along the  cold form and thus causes the formation of a thunderstorm where enough moisture is present and  drop in temperature occurs and in the northern hemisphere the cold front shifts the winds to from the southwest to northwest clockwise.
8 0
3 years ago
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