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Ivanshal [37]
3 years ago
6

What happens when you mix Mercury and Lead together?​

Chemistry
1 answer:
Cloud [144]3 years ago
8 0

Answer:

Lead forms an amalgam when filings are mixed with mercury and is also listed as a naturally occurring alloy called leadamalgam in the Nickel Strunz classification.

Explanation:

Brainliest please?

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What is a horizontal row of elements on a periodic table
Mariulka [41]

They are called Periods. Lesser known as series

3 0
3 years ago
Read 2 more answers
In the following reaction, how many grams of NaBr will react with 311 grams of Pb(NO3)2?
Mashutka [201]
Molar mass :

NaBr = 103 g/mol

Pb(NO3)2 = 331.20 g/mol

<span><span /><span>Balanced chemical equation :

</span></span>2 NaBr + 1 Pb(NO3)2 = 2 NaNO3 + 1 PbBr<span>2
</span><span>
2*103 g NaBr ------------> 1 * 331.20 g Pb(NO3)2
      g NaBr  -------------------> 311 g Pb(NO3)2

331.20  g  =   2*103*311

331.20 g = 64066

mass ( NaBr ) =  64066 / 331.20

mass ( naBr)  = 193,43 g of NaBr

hope this helps!.


</span>
5 0
3 years ago
How do I convert 125000g to scientific notation?
lakkis [162]
1.25000 multiply by 10^5
4 0
3 years ago
When Rutherford ran his gold foil experiment, he expected to see results like those in the Plum Pudding Atom simulation. Instead
DENIUS [597]

Rutherford's result can not be explained on the basis of the plum pudding model because of the fact that, since some alpha particles were deflected, the atom must contain a small region with a strong electric charge.

The empirical study of the atom led to the emergence of several models of the atom. In the Plum - pudding model, the atom was regarded as a positively charged sphere with embedded negative charges.

This model can not interpret the Rutherford experiment since alpha particles were deflected. The deflection of alpha particles means that, the atom must contain a small region with a strong electric charge.

Learn more: brainly.com/question/730256

4 0
2 years ago
If there is a loss of 5.63 x 10-7kg of mass in a nuclear reaction, how many Joules of energy would be released? Recall that c =
Fudgin [204]
Thank you for posting your question here at brainly. 

E = mc^2 
<span>where E is the energy in joules, </span>
<span>m is the mass in kilograms, </span>
<span>and c is the speed of light. </span>

<span>E = mc^2 </span>
<span>E = (5.63 x 10^-7 kg)(3 x 10^8 m/s)^2 </span>
<span>E = 5.07 x 10^10 J </span>


5 0
4 years ago
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