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2 years ago

What is the area of a rectangle with a width of x2 + x + 1 and a length of 3x2 - 2x - 1?

Mathematics

1 answer:

nata0808 [166]2 years ago

7 0

Answer:

$x^{4}$ + 3x³ - 3x - 1

Step-by-step explanation:

The area (A) of a rectangle is calculated as

A = lw ( l is the length and w the width ) , thus

A = (3x² - 2x - 1)(x² + x + 1)

Each term in the second factor is multiplied by each term in the first factor, then

A = 3x²(x² + x + 1) - 2x(x² + x + 1) - 1(x² + x + 1) ← distribute parenthesis

= 3 $x^{4}$ + 3x³ + 3x² - 2 $x^{4}$ - 2x² - 2x - x² - x - 1 ← collect like terms

= $x^{4}$ + 3x³ - 3x - 1

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andreev551 [17]

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2 years ago

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Answer:

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