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zvonat [6]
3 years ago
5

When the atom's electrons step down to lower energy levels in a thin cloud of hot gas, what is produced?

Physics
2 answers:
Reika [66]3 years ago
8 0

Answer: The correct answer is an emission line spectrum.

Explanation:

When the electrons are excited to the higher energy level, the energy is absorbed in this case.

When the electrons in the atom step down to lower energy levels in a thin cloud of hot gas then the radiation will emit.

The electron will lose energy in this case in the form of radiation. There will be an emission line spectrum.

ryzh [129]3 years ago
7 0

When the electrons step down to lower energy level, emission line spectrum produced.

Further Explanation:

The spectrum of emission of an element is spectrum of wavelength of radiation emitted during the transition of electron from a higher energy level to lower energy level. The energy of photon emitted in this process is equal to difference between the two levels. There is possibility of different types of transition for an atom and energy difference is specific for each atom.

When electrons are excited in atom, extra energy forces electrons to higher energy orbital. When electron goes to lower state, energy releases in form of photon. This emitted photon form the emission line spectrum.

Emission is process in which higher energy state of the particle convert into a lower state through the emission of photon, which produces light. The frequency of emitted light is function of transitional energy.

Since energy of system conserved, difference in energy between two states equal to energy carried by photon. The energy state of transitions results in emission of large frequency range.

Learn more:

1. Broadcast wavelength of station: brainly.com/question/9527365

2. Stress under the tension: brainly.com/question/12985068

3. Average translational kinetic energy: brainly.com/question/9078768

Answer Details:

Grade: High School

Subject: Physics

Chapter: Modern physics

Keywords:

Electrons, step, lower, energy, levels, thin, cloud, hot, gas, emission, line, spectrum, ground, state, higher, radiation, transition, energy, light and photon.

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Tanya [424]

Answer:

Average speed = 3.63 m/s

Explanation:

The average speed during any time interval is equal to the total distance travelled divided by the total time.

That is,

Average speed = distance/ time

Let d represent the distance between A and B.

Let t1 be the time for which she has the higher speed of 5.15 m/s. Therefore,

5.15 = d/t1.

Make d the subject of formula

d = 5.15t1

Let t2 represent the longer time for the return trip at 2.80 m/s . That is,

2.80 = d/t2.

Then the times are t1 = d/5.15 5 and

t2 = d/2.80.

The average speed vavg is given by the following equation.

avg speed = Total distance/Total time

Avg speed = d + d/t1 + t2

Where

Total distance = 2d

Total time = t1 + t2

Total time = d/5.15 + d/2.80

Total time = (2.8d + 5.15d)/14.42

Total time = 7.95d/14.42

Total time = 0.55d

Substitute total distance and time into the formula above.

Avg speed = 2d / 0.55d

Avg Speed = 3.63 m/s

7 0
3 years ago
As a mercury atom absorbs a photon of
Allisa [31]
The energy absorbed by photon is 1.24 eV.
This is the perfect answer.
8 0
3 years ago
What is the resistance of a voltage of 65 V and a current of 2.2 A? Include units.
kozerog [31]

Answer:

29.5 ohms

Explanation:

R= V/I

= 65 / 2.2

= 29.5 ohms

4 0
3 years ago
A fully loaded cart with a mass of 2200 kg starts from the top of a 12-meter hill on a roller coaster.
Salsk061 [2.6K]

Answer:

A. potential energy is 258720 Joule

Explanation:

A.Gravitational potential energy is: PE = m × g × h

velocity =  15.33 m/s when the car reaches the bottom of the hill.

where, m = mass

            g = acceleration due to gravity

            h = height from the bottom of hill.

The potential energy is : m×g×h

                                     =(2200×9.8×12)

                                     =258720 Joule

B. at the bottom of the hill, the potential energy is converted into kinetic energy so PE at top = KE at bottom

                    kinetic energy= \frac{1}{2}(m*v^{2})

where v = velocity

          m= mass

therefore,               v=\sqrt\frac{2*K.E}{m} {}

                         or,  v=\sqrt{\frac{2*258720}{2200} }

                         or,   v=15.33 m/s

7 0
3 years ago
Which object has more gravitational potential energy? Use PE = m × g × h, where g = 9.8 meters/second2.
Andrew [12]
Gravitational potential energy can be calculated using the formula <span>PE = m × g × h, where g is the gravitational acceleration and is constant hence the energy is dependent directly to mass and the height of the object. Hence more PE is registered when the object is heavier and/or at greater initial height. </span>
6 0
3 years ago
Read 2 more answers
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