When the atom's electrons step down to lower energy levels in a thin cloud of hot gas, what is produced?
2 answers:
When the electrons step down to lower energy level, emission line spectrum produced.
Further Explanation:
The spectrum of emission of an element is spectrum of wavelength of radiation emitted during the transition of electron from a higher energy level to lower energy level. The energy of photon emitted in this process is equal to difference between the two levels. There is possibility of different types of transition for an atom and energy difference is specific for each atom.
When electrons are excited in atom, extra energy forces electrons to higher energy orbital. When electron goes to lower state, energy releases in form of photon. This emitted photon form the emission line spectrum.
Emission is process in which higher energy state of the particle convert into a lower state through the emission of photon, which produces light. The frequency of emitted light is function of transitional energy.
Since energy of system conserved, difference in energy between two states equal to energy carried by photon. The energy state of transitions results in emission of large frequency range.
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Answer Details:
Grade: High School
Subject: Physics
Chapter: Modern physics
Keywords:
Electrons, step, lower, energy, levels, thin, cloud, hot, gas, emission, line, spectrum, ground, state, higher, radiation, transition, energy, light and photon.
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Answer:
18s
Explanation:
Given parameters:
Work done by hamster = 180J
Power of hamster = 10W
Uknown:
Time taken for the hamster to generate the work = ?
Solution:
Power can be defined as the rate at which work is being done by a body. It is related to both work done and time by the expression below;
Power =
Time taken =
Time taken = = 18s
The capacitance of a pair of a circular plates is(C) =8.90× 10⁻¹¹ F
<h3 /><h3>How can we calculate the value of capacitance?</h3>To calculate the value of the capacitance of a pair of a circular plates we are using the formula,
C= K
Here we are given,
K= Dielectric constant of mica.
=6.
A= the area of the circular plates.
= r²
(Note: r is the radius of the circular plates
= 4.0 cm
= 0.04 m)
= × (0.04)²
= permittivity of the vacuum
= 8.854×10⁻¹² F⋅m⁻¹
d= Separating distance of the plates
= 3.0 mm
= 0.003 m
now we put the known values in the above equation, we get
C= K
Or, C=
Or, C= 8.90× 10⁻¹¹ F
From the above calculation we can conclude that, The capacitance of a pair of a circular plates is(C) =8.90× 10⁻¹¹ F
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