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3 years ago

When the atom's electrons step down to lower energy levels in a thin cloud of hot gas, what is produced?

Physics

2 answers:

Reika [66]3 years ago

8 0

Answer: The correct answer is an emission line spectrum.

Explanation:

When the electrons are excited to the higher energy level, the energy is absorbed in this case.

When the electrons in the atom step down to lower energy levels in a thin cloud of hot gas then the radiation will emit.

The electron will lose energy in this case in the form of radiation. There will be an emission line spectrum.

ryzh [129]3 years ago

7 0

When the electrons step down to lower energy level, emission line spectrum produced.

Further Explanation:

The spectrum of emission of an element is spectrum of wavelength of radiation emitted during the transition of electron from a higher energy level to lower energy level. The energy of photon emitted in this process is equal to difference between the two levels. There is possibility of different types of transition for an atom and energy difference is specific for each atom.

When electrons are excited in atom, extra energy forces electrons to higher energy orbital. When electron goes to lower state, energy releases in form of photon. This emitted photon form the emission line spectrum.

Emission is process in which higher energy state of the particle convert into a lower state through the emission of photon, which produces light. The frequency of emitted light is function of transitional energy.

Since energy of system conserved, difference in energy between two states equal to energy carried by photon. The energy state of transitions results in emission of large frequency range.

Learn more:

1. Broadcast wavelength of station: brainly.com/question/9527365

2. Stress under the tension: brainly.com/question/12985068

3. Average translational kinetic energy: brainly.com/question/9078768

Answer Details:

Grade: High School

Subject: Physics

Chapter: Modern physics

Keywords:

Electrons, step, lower, energy, levels, thin, cloud, hot, gas, emission, line, spectrum, ground, state, higher, radiation, transition, energy, light and photon.

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A square current-carrying loop is placed in a uniform magnetic field B with the plane of the loop parallel to the magnetic field

lina2011 [118]

Answer:

The magnetic field exerts net force and net torque on the loop.

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3 years ago

What velocity will a freefalling object have after falling 80 meters

vovangra [49]

Answer:

129.96

At a Gravitational acceleration of 32.17405 ( which is the normal rate for a freefall) you will geta velocity of 129.96 and the time of fall will be 4.039 seconds from 80 meters.

Why is the weight of a free falling body zero? It is not, an object in free fall will still have a weight, governed by the equation W = mg, where W is the object's weight, m is the object's mass, and g is acceleration due to gravity. Weight, however, has no effect on an objects free falling speed, two identically shaped objects weighing a different amount will hit the ground at the same time.

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3 years ago

(12 points) Analysis from the point where the block is released to the point where it reaches the maximum height i) Calculate th

ycow [4]

Answer:

i) a₁ = -g (sin θ + μ cos θ), x = v₀² / 2a₁

ii) W = mg L sin θ , iii) Wₙ = 0

iv) W = - μ m g L cos θ x

Explanation:

With a drawing this exercise would be clearer, I understand that you have a block on a ramp and it is subjected to some force that makes it rise, for example the tension created by a descending block.

The movement is that when the system is released, the tension forces are greater than the friction and the component of the weight and therefore the block rises up the ramp

At some point the tension must become zero, when the hanging block reaches the ground, as the block has a velocity it rises with a negative acceleration to a point and stops where the friction force and the weight component would be in equilibrium along the way. along the plane

i) Let's use Newton's second law

the reference system is with the x axis parallel to the ramp

Axis y

N - W cos θ = 0

X axis

T - W sin θ - fr = ma

the friction force is

fr = μ N

fr = μ mg cos θ

we substitute

T - m g sin sin θ - μ mg cos θ = m a

a = T / m - g (sin θ + μ cos θ)

With this acceleration we can find the height that the block reaches, this implies that at some point the tension becomes zero, possibly when a hanging block reaches the floor.

T = 0

a₁ = -g (sin θ + μ cos θ)

v² = v₀² - 2a1 x

v = 0 at the highest point

x = v₀² / 2a₁

ii) the work of the gravitational force is

W = F .d

W = mg sin θ L

iii) the work of the normal force

the force has 90º with respect to the displacement so cos 90 = 0

Wₙ = 0

iv) friction force work

friction force always opposes displacement

W = - fr d

W = - μ m g cos θ L

4 0

3 years ago

A 2.0 kg cart has a momentum of 10.0 kg m/s. What is its velocity?

Svetach [21]

Answer:

$\boxed {\boxed {\sf C. \ 5.0 \ m/s}}$

Explanation:

Momentum is the product of mass and velocity. The formula is:

$p=mv$

The mass of the cart is 2.0 kilograms. The momentum is 10.0 kg m/s. The velocity is unknown.

$m= 2.0 \ kg \\p= 10.0 \ kg \ m/s$

Substitute the values into the formula.

$10.0 \ kg \ m/s= (2.0 \ kg ) v$

We want to solve for the velocity (v). Therefore we must isolate the variable. It is being multiplied and the inverse of multiplication is division. Divide both sides of the equation by 2.0 kg.

$\frac { 10.0 \ kg \ m/s}{2.0 \ kg}=\frac{(2.0 \ kg )v}{2.0 \ kg}$