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zvonat [6]
3 years ago
5

When the atom's electrons step down to lower energy levels in a thin cloud of hot gas, what is produced?

Physics
2 answers:
Reika [66]3 years ago
8 0

Answer: The correct answer is an emission line spectrum.

Explanation:

When the electrons are excited to the higher energy level, the energy is absorbed in this case.

When the electrons in the atom step down to lower energy levels in a thin cloud of hot gas then the radiation will emit.

The electron will lose energy in this case in the form of radiation. There will be an emission line spectrum.

ryzh [129]3 years ago
7 0

When the electrons step down to lower energy level, emission line spectrum produced.

Further Explanation:

The spectrum of emission of an element is spectrum of wavelength of radiation emitted during the transition of electron from a higher energy level to lower energy level. The energy of photon emitted in this process is equal to difference between the two levels. There is possibility of different types of transition for an atom and energy difference is specific for each atom.

When electrons are excited in atom, extra energy forces electrons to higher energy orbital. When electron goes to lower state, energy releases in form of photon. This emitted photon form the emission line spectrum.

Emission is process in which higher energy state of the particle convert into a lower state through the emission of photon, which produces light. The frequency of emitted light is function of transitional energy.

Since energy of system conserved, difference in energy between two states equal to energy carried by photon. The energy state of transitions results in emission of large frequency range.

Learn more:

1. Broadcast wavelength of station: brainly.com/question/9527365

2. Stress under the tension: brainly.com/question/12985068

3. Average translational kinetic energy: brainly.com/question/9078768

Answer Details:

Grade: High School

Subject: Physics

Chapter: Modern physics

Keywords:

Electrons, step, lower, energy, levels, thin, cloud, hot, gas, emission, line, spectrum, ground, state, higher, radiation, transition, energy, light and photon.

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Verizon [17]

Answer:

1. Running velocity (5 m/s)

2. Resting velocity (0 m/s)

3. Walking velocity (-1 m/s)

1. Running speed (5 m/s)

2. Walking speed (1 m/s)

3. Resting speed (0 m/s)

Explanation:

Attached you will find the plot of position vs time of Ellie´s movement.

The velocity is the displacement of the object over time relative to the system of reference. The speed, in change, is the traveled distance over time in disregard of the system of reference.

So, the velocity is calculated as follows:

v = Δx / Δt

where

Δx = final position - initial position

Δt = elapsed time

1) The average velocity of Ellie while running is:

v = 1000 m - 0 m / 200 s = 5 m/s

While resting:

v = 0 m - 0 m / 100 s = 0 m/s

And while walking back:

v = 0 m - 1000 m / 1000 s = - 1 m/s

Note that in this last case, the initial position is 1000 m because Ellie is 1000 m from the origin of the system of reference when she walks back. The final position will be the origin of the system of reference, 0 m.

Comparing with the graphic, the velocity is the slope of the function position(t).

Then:

1. Running velocity (5 m/s)

2. Resting velocity (0 m/s)

3. Walking velocity (-1 m/s)

2) The speed is the distance traveled over time:

Running speed = 1000 m / 200 s = 5m /s

Resting speed = 0 m / 100 s = 0 m/s

Walking speed = 1000 m/ 1000 s = 1 m/s

Then:

1. Running speed (5 m/s)

2. Walking speed (1 m/s)

3. Resting speed (0 m/s)  

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shusha [124]
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Butoxors [25]

Answer:

T = 0.003 s

(Period is written as T)

Explanation:

Period = time it takes for one wave to pass (measured in seconds)

frequency = number of cycles that occur in 1 second

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Period : T

frequency : f

So, if we know that the frequency of a wave is 300 Hz, we can find the period of the wave from the relation between frequency and period

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