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Allushta [10]
3 years ago
9

There is an electric field in the region between the two plates. The magnitude of this electric field is ed. This imposes anothe

r condition on the charge densities on the surfaces of the plates. How can this condition be expressed?
Physics
1 answer:
Alik [6]3 years ago
6 0

Answer:

it is essential that the charge on the plates are of the same magnitude, but in the opposite direction

Explanation:

The configuration of parallel plates is called a capacitor and is widely used to create constant electric fields inside.

 To obtain this field it is essential that the charge on the plates are of the same magnitude, but in the opposite direction

This is so that the fields created by each plate can be added inside and subtracted from the outside of the plates

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Answer:

You would need to save $300 every month to meet your savings goal.

Explanation:

4,500-900=3,600

3,600/12=300

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The correct answer is C
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A prism is a cut piece of clear glass or plastic in the form of a triangular prism that separates white light into a spectrum th
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Explanation:

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two teams are playing tug of war. team a pulls to the right with a force of 450n .team b pulls to the left with a force of 415 n
Alex_Xolod [135]

Explanation:

It is given that, two teams are playing tug of war.

Force applied by Team A, F_A=450\ N

Force applied by Team B, F_B=415\ N

We need to find the net force acting on the rope. It is equal to :

F_{net}=F_A-F_B

F_{net}=450-415

F_{net}=35\ N

So, the net force acting on the rope is 35 N and it is acting toward right. Hence, this is the required solution.

4 0
3 years ago
A girl swings on a playground swing in such a way that at her highest point she is 4.1 m from the ground, while at her lowest po
Umnica [9.8K]

Answer:

V1 =8.1 m/s

Explanation:

height at highest point (h2) = 4.1 m

height at lowest point (h1) = 0.8 m

acceleration due to gravity (g) = 9.8 m/s^{2}

from conservation of energy, the total energy at the lowest point will be the same as the total energy at the highest point. therefore

mgh1 + 0.5mV1^{2} = mgh2 + 0.5mV2^{2}

where

  • speed at highest point = V2
  • speed at lowest point = V1
  • mass of the girl and swing = m
  • at the highest point, the  speed is minimum (V1 = 0)
  • at the lowest point the speed is maximum (V2 is the maximum speed)
  • therefore the equation becomes mgh1 + 0.5mV1^{2} = mgh2

      m(gh1 + 0.5V1^{2}) = m(gh2)

      gh1 + 0.5V1^{2} = gh2

      V1 = \sqrt{\frac{gh2 - gh1}{0.5}}

now we can substitute all required values into the equation above.

V1 = \sqrt{\frac{(9.8x4.1) - (9.8x0.8)}{0.5}}

V1 = \sqrt{\frac{32.34}{0.5}}

V1 =8.1 m/s

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4 years ago
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