Ask question

Ask question

All categories

3 years ago

13

If questions asked in a research study to do not accurately relate to the subject or construct being studied, the study’s ______

____ is compromised. A. population B. evaluation C. administration D. validity Please select the best answer from the choices provided A B C D

1 answer:

Elina [12.6K]3 years ago

4 0

Answer: d

Explanation: Did it on Ed2020 got it right

You might be interested in

Your electric drill rotates initially at 5.21 rad/s. You slide the speed control and cause the drill to undergo constant angular

RUDIKE [14]

Answer:

The drill's angular displacement during that time interval is 24.17 rad.

Explanation:

Given;

initial angular velocity of the electric drill, $\omega _i$ = 5.21 rad/s

angular acceleration of the electric drill, α = 0.311 rad/s²

time of motion of the electric drill, t = 4.13 s

The angular displacement of the electric drill at the given time interval is calculated as;

$\theta = \omega _i t \ + \ \frac{1}{2}\alpha t^2\\\\\theta = (5.21 \ \times \ 4.13) \ + \ \frac{1}{2}(0.311)(4.13)^2\\\\\theta = (21.5173 ) \ + \ (2.6524)\\\\\theta =24.17 \ rad$

Therefore, the drill's angular displacement during that time interval is 24.17 rad.

6 0

3 years ago

Does anyone taste the difference between left and right twix?

4vir4ik [10]

I personally don't (I can't speak for others tho) but I say right twix is better for the memes

3 0

3 years ago

What is the momentum of a 1550kg car that is traveling 38.0 m/s?

konstantin123 [22]

Answer:

p = 58,900 kg m/s

Explanation:

p = m × v

p = 1,550 × 38.0

p = 58,900 kg m/s

5 0

2 years ago

I need the correct answer for this question please

kirill115 [55]

Try C. a downward gravitational force exerted by Earth

7 0

2 years ago

B. Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the

goblinko [34]

We have that the instantaneous velocity of the shuttlecock when it hits the ground is

$V_{int}=\sqrt{U^2+19.6H}$

From the question we are told

Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the

shuttlecock when it hits the ground? Show your work below.

Generally the equation for acceleration is mathematically given as

$a=v \frac{dv}{dx}\\\\\Therefore\\\\\2ah=v^2-u^2$

Where

acceleration is still -9.81 m/s2,

Hence,

$V^2-U^2=2(-9.81)*-H$

Therefore

$V_{int}=\sqrt{U^2+19.6H}$

For more information on this visit

brainly.com/question/12319416?referrer=searchResults

7 0

2 years ago