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faltersainse [42]
3 years ago
7

The stair stepper is a novel exercise machine that attempts to reproduce the work done against gravity by walking up stairs. Wit

h each step, Brad (of mass 60 kg) simulates stepping up a vertical distance of 0.2 m with this machine. If Brad exercises for 13 min per day with a stair stepper at a frequency of 50 steps per minute, what total work he does he do each day
Physics
1 answer:
Delicious77 [7]3 years ago
7 0

Answer:

W = 76518 J = 76.518 KJ

Explanation:

First, we will find the total number of steps taken by Brad, as follows:

No.\ of\ steps = n = (13\ min)(50\ steps/min) = 650\ steps\\

Now, we will calculate the height covered while covering these number of steps:

Height\ Covered = H = (n)(Height\ for\ 1\ step)\\\\H = (0.2\ m/step)(650\ steps)\\H = 130\ m

Now, we will calculate the amount of work done while covering this distance:

Work = W = mgH = \\W = (60\ kg)(9.81\ m/s^2)(130\ m)

<u>W = 76518 J = 76.518 KJ</u>

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An airplane has wings, each with area A, designed so that air flows over the top of the wing at 265 m/s and underneath the wing
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Answer

given,

Pressure on the top wing = 265 m/s

speed of underneath wings = 234 m/s

mass of the airplane =  7.2 × 10³ kg

density of air =  1.29 kg/m³

using Bernoulli's equation

 P_1 + \dfrac{1}{2}\rho v_1^2 = P_2 + \dfrac{1}{2}\rho v_2^2

 \Delta P =\dfrac{1}{2}\rho (v_2^2-v_1^2)

 \Delta P =\dfrac{1}{2}\times 1.29\times (265^2-234^2)

 \Delta P =9977.5 Pa

Applying newtons second law

2 Δ P x A - mg = 0

A =\dfrac{mg}{2\Delta P}

A =\dfrac{7.2\times 10^3 \times 9.8}{2\times 9977.5}

    A = 3.53 m²

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