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faltersainse [42]
3 years ago
7

The stair stepper is a novel exercise machine that attempts to reproduce the work done against gravity by walking up stairs. Wit

h each step, Brad (of mass 60 kg) simulates stepping up a vertical distance of 0.2 m with this machine. If Brad exercises for 13 min per day with a stair stepper at a frequency of 50 steps per minute, what total work he does he do each day
Physics
1 answer:
Delicious77 [7]3 years ago
7 0

Answer:

W = 76518 J = 76.518 KJ

Explanation:

First, we will find the total number of steps taken by Brad, as follows:

No.\ of\ steps = n = (13\ min)(50\ steps/min) = 650\ steps\\

Now, we will calculate the height covered while covering these number of steps:

Height\ Covered = H = (n)(Height\ for\ 1\ step)\\\\H = (0.2\ m/step)(650\ steps)\\H = 130\ m

Now, we will calculate the amount of work done while covering this distance:

Work = W = mgH = \\W = (60\ kg)(9.81\ m/s^2)(130\ m)

<u>W = 76518 J = 76.518 KJ</u>

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A rope has a mass of 10.43 pounds per meter. Express this in milligrams per centimeter.
gregori [183]

Answer:

47347.1936 milligrams per centimeter

Explanation:

1 pound is equal 453592 milligrams.

one meter is 100cm

10.43*453952/100= 47347.1936milligrams per cm

3 0
4 years ago
Convert 162 km/h into m/s.
patriot [66]

Answer:

45 m/s

Explanation:

162 / 3.6 = 45 m/s

Divide by 3.6 to convert km/h to m/s.

4 0
3 years ago
Resistors 1 and 2− R1 = 50 Ω , R2 = 90 Ω − are connected in series to a 6.0-V battery. Part APart complete What is the potential
kondor19780726 [428]

Answer:

Part A: The voltage across resistor R1 is approximately \rm 2.1 \; V.

Part B: When the value of resistor R1 decreases, the current in this circuit will increase.

Part C: When the value of resistor R1 decreases, the voltage across resistor R1 will decrease.

Explanation:

<h3>Part A</h3>

Resistor R1 and and R2 are connected in series. That's equivalent to a single resistor of R_1 + R_2 = 50 + 90 = 140\; \Omega. The voltage across the two resistor, combined, is equal to \rm 6\; V. Hence by Ohm's Law, the current through the circuit will be equal to \rm \dfrac{6\; V}{140\; \Omega} = \dfrac{3}{70}\; A.

These two resistors are connected in series. The voltage across each of them might differ. However, the current through each of them should both be equal to the current through the circuit. In this case, the current through both R1 and R2 should be equal to \rm \dfrac{3}{70}\; A. Apply Ohm's Law (again) to find the voltage across R1:

V = I \cdot R = \dfrac{3}{70} \times 50 \approx \rm 2.1\; V.

<h3>Part B</h3>

Since the equivalent resistance is equal to R_1 + R_2, when the value of R_1 decreases, the equivalent resistance will also decrease. By Ohm's Law, I = \dfrac{V}{R}. When the value of the denominator ( decreases, the value of the quotient, I the current through the circuit, will increase.

<h3>Part C</h3>

Keep in mind that if two resistors are connected in series,

I(R_1) = I(\text{Circuit}) = I(R_2).

The resistance of R1 decreases, while the current through it increases. Applying Ohm's Law on R1 won't give much useful information. However, since the resistance of R2 stays the same, the voltage across it will increase when its current increases (again by Ohm's Law.)

Again, since the two resistors are connected in series,

V(R_1) + V(R_2) = V(\text{Circuit}) = \rm 6 \; V,

when the voltage across R2 increases, the voltage across R1 will decrease.

4 0
3 years ago
PLEASE HELP ASAP!!! NO LINKS! Which type of wave does the illustration depict?
Xelga [282]

Answer:

Transverse wave

Explanation:

The wave is moving forwards from the hand to the point of attachment

3 0
3 years ago
A 4-foot spring measures 8 feet long after a mass weighing 8 pounds is attached to it. The medium through which the mass moves o
aniked [119]

Correct question is;

A 4-foot spring measures 8 feet long after a mass weighing 8 pounds is attached to it. The medium through which the mass moves offers a damping force numerically equal to √2 times the instantaneous velocity. Find the equation of motion if the mass is initially released from the equilibrium position with a downward velocity of 7 ft/s. (Use g = 32 ft/s²)

Answer:

x(t) = 7te^(-2t√2)

Explanation:

We are given;

Weight; W = 8 lbs

mass; m = W/g

g = 32 ft/s²

Thus;

m = 8/32

m = ¼ slugs

From Newton's second law we can write the equation as;

m(d²x/dt²) = -kx - β(dx/dt)

Rearranging this, we have;

(d²x/dt²) + (β/m)(dx/dt) + (k/m)x = 0

Where;

β is damping constant = √2

k is spring constant = W/s

Where s = 8ft - 4ft = 4ft

k = 8/4

k = 2

Thus,we now have;

(d²x/dt²) + (√2/(¼))(dx/dt) + (2/(¼))x = 0

>> (d²x/dt²) + (4√2)dx/dt + 8x = 0

The auxiliary equation of this is;

m² + (4√2)m + 8 = 0

Using quadratic formula, we have;

m1 = m2 = -2√2

The general solution will be gotten from;

x_t = c1•e^(mt) + c2•t•e^(mt)

Plugging in the relevant values gives;

x_t = c1•e^(mt) + c2•t•e^(mt)

At initial condition of t = 0, x_t = 0 and thus; c1 = 0

Also at initial condition of t = 0, x'(0) = 7 and thus;

Since c1 = 0, then c2 = 7

Thus,equation of motion is;

x(t) = 7te^(-2t√2)

8 0
3 years ago
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