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PSYCHO15rus [73]

3 years ago

5

A ________________ in a transverse wave corresponds to a compression in a longitudinal wave

1 answer:

cluponka [151]3 years ago

3 0

The answer is Crest in transverse waves, this is where the particles are closest to each other due to the compression of the longitudinal component of the wave.

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If the strings have different thicknesses, which of the following parameters, if any, will be different in the two strings?.

cricket20 [7]

Answer:

Wave speed and wavelength

Explanation:

6 0

2 years ago

Please help im failing!!!

natta225 [31]

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5 0

3 years ago

A beam of yellow light is made to pass through two slits that are 3.0 x 10−3 meters apart. On a screen 2.0 meters away from the

lakkis [162]

Answer:

585 nm

Explanation:

The formula that gives the position of the m-th maximum (bright fringe) relative to the central maximum in the interference pattern produced by diffraction from double slit is:

$y=\frac{m\lambda D}{d}$ $\Delta y =\frac{m\lambda D}{d}$

where

m is the order of the maximum

$\lambda$ is the wavelength

D is the distance of the screen from the slits

d is the separation between the slits

The distance between two consecutive bright fringes therefore is given by:

$\Delta y = \frac{(m+1)\lambda D}{d}-\frac{m\lambda D}{d}=\frac{\lambda D}{d}$

In this problem we have:

$\Delta y = 3.9\cdot 10^{-4} m$ (distance between two bright fringes)

D = 2.0 m (distance of the screen)

d = 3.0 x 10−3 m (separation between the slits)

Solving for $\lambda$ , we find the wavelength:

$\lambda=\frac{\Delta y d}{D}=\frac{(3.9\cdot 10^{-4})(3.0\cdot 10^{-3})}{2.0}=5.85\cdot 10^{-7} m = 585 nm$

4 0

3 years ago

What pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c?

Ronch [10]

The pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.

Therefore, option A is correct option.

Given,

Mass m = 14g

Volume= 3.5L

Temperature T= 75+273 = 348 K

Molar mass of CO = 28g/mol

Universal gas constant R= 0.082057L

Number of moles in 14 g of CO is

n= mass/ molar mass

= 14/28

= 0.5 mol

As we know that

PV= nRT

P × 3.5 = 0.5 × 0.082057 × 348

P × 3.5 = 14.277

P = 14.277/3.5

P = 4.0794 atm

P = 4.1 atm.

Thus we concluded that the pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.

learn more about pressure:

brainly.com/question/22613963

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5 0

1 year ago

Heelppp please ASAP !!!!!

Masja [62]

39.2 m/s
Since 9.8 is the acceleration of gravity times 4 gives you 39.2

4 0

3 years ago