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lubasha [3.4K]
3 years ago
14

4 to the power of 2 -3 (7+4)

Mathematics
2 answers:
leva [86]3 years ago
8 0

Answer:

-17

Step-by-step explanation:

Vaselesa [24]3 years ago
7 0

Answer:

-17

Step-by-step explanation:

lol

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Please help I would love it if you do (math)
beks73 [17]
This question is basically asking you what number was this originally until we timesed it by 100. For the first column take away two zeros or for answers like 560 and 4830 imagine there is a decimal point at the end and move it two spaces forward so it would now be 5.6 and 48.3

For the second column add two zeros at the end instead.

For the questions at the bottom basically for all the questions except the bottom one how many numbers follow the first number.

For example.

96,629 = 1
100

Because three numbers follow the first 6.

Hope this makes sense because I don’t know if it does.
3 0
3 years ago
Evaluate the expression 72/x2-2 for x=3
Rzqust [24]

Answer:46

Step-by-step explanation:

7 0
3 years ago
For problems 11-14, identify the property shown. 11. 16×p=16.​
zalisa [80]

Answer:

Step-by-step explanation:

11. identity property

12. associative property

13. commutative property

14. zero property

4 0
2 years ago
Which can be solved by using square roots? Choose all that apply. (Hint: Make sure each equation is set equal to 0 before you ma
Masteriza [31]

Answer: I don't know

Step-by-step explanation:

5 0
3 years ago
Alabama Instruments Company has set up a production line to manufacture a new calculator. The rate of production of these calcul
umka21 [38]

Answer:

The number of calculators is 4871

Step-by-step explanation:

If we integrate dx/dt we get x, which is the number of calculators. To find the number of calculators between the beginning of third week to the end of fourth week (the beginning of fifth week), this integration must be evaluated at t between 3 and 5.

x=\int\limits^5_3 {\frac{dx}{dt}} \, dt =\int\limits^5_3 {5000(1-\frac{100}{(t+10)^2})} \, dt

the result of the integration is:

x=5000(t+\frac{100}{t+10}) to be evaluated between 3 and 5, which is:

x=5000(5+\frac{100}{5+10})-5000(3+\frac{100}{3+10})=\frac{190000}{39}=4871.8

6 0
3 years ago
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