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katovenus [111]
3 years ago
12

Evaluate the expression: 3x + 2y when X=10 and y=4

Mathematics
2 answers:
sveta [45]3 years ago
5 0

Answer:

38

Step-by-step explanation:

3x + 2y when X=10 and y=4

3(10) + 2(4)

30 + 8

38

Verizon [17]3 years ago
5 0
The answer is 38 :)
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Uhhh-
Step2247 [10]

Step-by-step explanation:

y = mx + c, where m is the slope of the line and c is the y-intercept.

We have y = 3x - 4 as line L.

Slope of line L = 3

=> Slope of line L2 = -1/3

We have y = -1/3 x + c as our line L2 equation.

When x = 9, y = 5.

=> (5) = -1/3 * (9) + c

=> 5 = c - 3, c = 8

Hence the answer is y = -1/3 x + 8.

8 0
3 years ago
Twenty Percent of the 4000 acres were plowed. how many acres were not plowed
Daniel [21]
20% was, so 100%-20%=80% was not
80%=0.8
0.8*4000=3200 acres was not
5 0
3 years ago
HELP PLS ITS DUE TOMMAROW ILL GIE BRAINLIST FOR THE CORRECT ANSWER
Tasya [4]
You just need to make them all the same common denominator. do you still need help?
4 0
3 years ago
Integer problems that equal 36
klio [65]
What integer is less than 37 but greater than 35?
5 0
3 years ago
CAN SOMEONE PLEASE ANSWER THISS ASAP PLEASE
solong [7]

Answer:

Step-by-step explanation:

11.04 = 10(1.02)^n

1.104 = 1.02^n

ln 1.104 = ln 1.02^n

ln 1.104 = n ln 1.02

n = ln 1.104/ ln 1.02

n = 4.99630409516

4.99 can be rounded to 5.

So a reasonable domain would be 0 ≤ x < 5

PART B)

f(0) = 10(1.02)^0

f(0) = 10(1)

f(0) = 10

The y-intercept represents the height of the plant when they began the experiment.

f(1) = 10(1.02)^1

f(1) = 10(1.02)

f(1) = 10.2

(1, 10.2)

f(5) = 10(1.02)^5

f(5) = 10(1.1040808)

f(5) = 11.040808

f(1)=10(1.02)^1

f(1)=10.2

Average rate= (fn2-fn1)/(n2-n1)

                     =11.04-10.2/(5-1)

                    =0.22

the average rate of change of the function f(n) from n = 1 to n = 5 is 0.22.  

8 0
3 years ago
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