Answer:
The buoyant force is a result of pressure exerted by the fluid. The fluid pushes on all sides of an immersed object, but as pressure increases with depth, the push is stronger on the bottom surface of the object than in the top
Explanation:
Answer:
the work done on the car by the applied force is 75 J.
Explanation:
Given;
initial velocity of the car, v = 4 m/s
applied force in opposite direction, F = 5N
initial position of the car, x₀ = 5 m
final position of the car, x₁ = 20 m
displacement of the car, Δx = x₁ - x₀ = 20 m - 5m
= 15 m
The work done on the car by the applied force is calculated as follows;
W = F.Δx
W = 5 x 15
W = 75 J
Therefore, the work done on the car by the applied force is 75 J.
Answer:
At the december solstice,the northern hemisphere is leaning most away from the sun for the year.At the december solatric,earth is positioned in its orbit so that the sun below the north pole horizon. After the winter solstice,the days get longer,and the night shorter.
Answer:
The force applied on one wheel during braking = 6.8 lb
Explanation:
Area of the piston (A) = 0.4
Force applied on the piston(F) = 6.4 lb
Pressure on the piston (P) =
⇒ P =
⇒ P = 16
This is the pressure inside the cylinder.
Let force applied on the brake pad =
Area of the brake pad ()= 1.7
Thus the pressure on the brake pad () =
When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.
⇒ P =
⇒ 16 =
⇒ = 16 ×
Put the value of we get
⇒ = 16 × 1.7
⇒ = 27.2 lb
This the total force applied during braking.
The force applied on one wheel = = = 6.8 lb
⇒ The force applied on one wheel during braking.