<h2>
Answer:</h2>
MT⁻¹
<h2>
Explanation:</h2>
Given equation:
F = Kv --------------(i)
Where;
F = Magnitude of force experienced by the object
v = speed at which the object is moving
K = constant.
To get the dimension of K, follow the following steps:
i. <em>Make K subject of the formula in equation(i)</em>
K = F / v
ii.<em> Get the dimension of force F and speed v</em>
Dimension of force = MLT⁻²
Dimension of velocity = LT⁻¹
iii.<em> Substitute these dimensions into the result of (i) above;</em>
K = MLT⁻² / LT⁻¹
iv. <em>Simplify the result in (iii)</em>
<em>First, the </em><em>L</em><em>s in the numerator and denominator will cancel out</em>
K = MT⁻² / T⁻¹
<em>Next, the </em><em>T</em><em>s will be expressed as follows</em>
K = MT⁻² x T¹ [using the law of indices]
K = MT⁻²⁺¹
K = MT⁻¹
Therefore, the dimension of K is MT⁻¹
