Answer:
⇒ 401.6 ± 7.1 ms
⇒ 57.2 ± 1.6 kg
⇒ 8.1 × 107 ± 2.9 × 105 m
⇒ 2.1 ± 8.8 µN
⇒ 294 ± 0.005 cm
Explanation:
As given all equation we do without calculation we will get here round these calculations which is given below as
a) 401.6473 ± 7.0912 ms
⇒ 401.6 ± 7.1 ms
b) 57.212 ± 1.612 kg
⇒ 57.2 ± 1.6 kg
c) 8.12754×107 ± 2.847×105 m
⇒ 8.1 × 107 ± 2.9 × 105 m
d) 2.94 ± 8.803 µN
⇒ 2.1 ± 8.8 µN
e) 294 ± 0.00481 cm
⇒ 294 ± 0.005 cm
Answer:
ºC
Explanation:
First, let's write the energy balance over the duct:

It says that the energy that goes out from the duct (which is in enthalpy of the mass flow) must be equals to the energy that enters in the same way plus the heat that is added to the air. Decompose the enthalpies to the mass flow and specific enthalpies:

The enthalpy change can be calculated as Cp multiplied by the difference of temperature because it is supposed that the pressure drop is not significant.

So, let's isolate
:

The Cp of the air at 27ºC is 1007
(Taken from Keenan, Chao, Keyes, “Gas Tables”, Wiley, 1985.); and the only two unknown are
and Q.
Q can be found knowing that the heat flux is 600W/m2, which is a rate of heat to transfer area; so if we know the transfer area, we could know the heat added.
The heat transfer area is the inner surface area of the duct, which can be found as the perimeter of the cross section multiplied by the length of the duct:
Perimeter:

Surface area:

Then, the heat Q is:

Finally, find the exit temperature:

=27.0000077 ºC
The temperature change so little because:
- The mass flow is so big compared to the heat flux.
- The transfer area is so little, a bigger length would be required.
MRI-Magnetic resonsance imaging
Look at the pic!! Hope
It helps love ❤️
Answer:
a) 4.9W b) 3.82W
Explanation:
Stefan-Boltzmann law of radiation formulae:
Q/t (W) = sigma* e*A*T^4
Sigma = 5.67*10^-8 j/sm^2K^4 (Stefano Boltzmann constant)
e = emissivity
T = absolute temperature in kelvin and A = area in m^2
a) Q/t = 140/10000(m^2) * 0.87* 5.67* 10^-8* (290^4) = 4.9W
b) without hair the
Q/t = 140/ 10000(m^2) *0.68* 5.67* 10^-8* (290^4)
= 3.82W
The answer is C.
they run east to west which makes them parallel to the equator and they measure distances north and south.
I hope this helps.