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Oksana_A [137]
3 years ago
7

Two balls have masses 18 kg and 47 kg. The 18 kg ball has an initial velocity of 76 m/s (to the right) along a line joining the

two balls and the 47 kg ball is at rest. They make a head-on elastic collision with each other. What is the final velocity of the 18 kg ball?
Physics
1 answer:
BigorU [14]3 years ago
3 0

Answer:

The final velocity of 18 kg ball is V_{2} = 42.09 \frac{m}{sec}

Explanation:

Mass of first ball m_{1} = 18 kg

Mass of second ball m_{2} = 47 kg

Initial velocity of 18 kg ball V_{1} = 76 \frac{m}{sec}

Initial velocity of 47 kg ball = 0

Final velocity of 18 kg ball V_{2} = ??

Final velocity of 18 kg ball  is given by the formula

V_{2} = \frac{2 m_{1} V_{1} }{m_{1} + m_{2}  }

Put all the values in above formula we get

V_{2} = 2 × 18 × \frac{76}{65}

V_{2} = 42.09 \frac{m}{sec}

Thus, the final velocity of 18 kg ball is V_{2} = 42.09 \frac{m}{sec}

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After performing some calculations, your calculator gives you the following results. How will you round them before presenting t
umka2103 [35]

Answer:

⇒ 401.6 ± 7.1 ms

⇒ 57.2 ± 1.6 kg

⇒ 8.1 × 107 ± 2.9 × 105 m

⇒ 2.1 ± 8.8 µN

⇒ 294 ± 0.005 cm

Explanation:

As given all equation we do without calculation we will  get here round these calculations which is given below as  

a) 401.6473 ± 7.0912 ms

⇒ 401.6 ± 7.1 ms

b) 57.212 ± 1.612 kg

⇒ 57.2 ± 1.6 kg

c) 8.12754×107 ± 2.847×105 m

⇒ 8.1 × 107 ± 2.9 × 105 m

d) 2.94 ± 8.803 µN

⇒ 2.1 ± 8.8 µN

e) 294 ± 0.00481 cm

⇒ 294 ± 0.005 cm

6 0
3 years ago
Air at 3 104 kg/s and 27 C enters a rectangular duct that is 1m long and 4mm 16 mm on a side. A uniform heat flux of 600 W/m2 is
ad-work [718]

Answer:

T_{out}=27.0000077 ºC

Explanation:

First, let's write the energy balance over the duct:

H_{out}=H_{in}+Q

It says that the energy that goes out from the duct (which is in enthalpy of the mass flow) must be equals to the energy that enters in the same way plus the heat that is added to the air. Decompose the enthalpies to the mass flow and specific enthalpies:

m*h_{out}=m*h_{in}+Q\\m*(h_{out}-h_{in})=Q

The enthalpy change can be calculated as Cp multiplied by the difference of temperature because it is supposed that the pressure drop is not significant.

m*Cp(T_{out}-T_{in})=Q

So, let's isolate T_{out}:

T_{out}-T_{in}=\frac{Q}{m*Cp}\\T_{out}=T_{in}+\frac{Q}{m*Cp}

The Cp of the air at 27ºC is 1007\frac{J}{kgK} (Taken from Keenan, Chao, Keyes, “Gas Tables”, Wiley, 1985.); and the only two unknown are T_{out} and Q.

Q can be found knowing that the heat flux is 600W/m2, which is a rate of heat to transfer area; so if we know the transfer area, we could know the heat added.

The heat transfer area is the inner surface area of the duct, which can be found as the perimeter of the cross section multiplied by the length of the duct:

Perimeter:

P=2*H+2*A=2*0.004m+2*0.016m=0.04m

Surface area:

A=P*L=0.04m*1m=0.04m^2

Then, the heat Q is:

600\frac{W}{m^2} *0.04m^2=24W

Finally, find the exit temperature:

T_{out}=T_{in}+\frac{Q}{m*Cp}\\T_{out}=27+\frac{24W}{3104\frac{kg}{s} *1007\frac{J}{kgK} }\\T_{out}=27.0000077

T_{out}=27.0000077 ºC

The temperature change so little because:

  • The mass flow is so big compared to the heat flux.
  • The transfer area is so little, a bigger length would be required.
3 0
3 years ago
Definition MRI<br> types MRI <br>explain MRI​
guajiro [1.7K]
MRI-Magnetic resonsance imaging
Look at the pic!! Hope
It helps love ❤️

5 0
3 years ago
A person is standing outdoors in the shade where the temperature is 17 °C. (a) What is the radiant energy absorbed per second by
Inessa05 [86]

Answer:

a) 4.9W b) 3.82W

Explanation:

Stefan-Boltzmann law of radiation formulae:

Q/t (W) = sigma* e*A*T^4

Sigma = 5.67*10^-8 j/sm^2K^4 (Stefano Boltzmann constant)

e = emissivity

T = absolute temperature in kelvin and A = area in m^2

a) Q/t = 140/10000(m^2) * 0.87* 5.67* 10^-8* (290^4) = 4.9W

b) without hair the

Q/t = 140/ 10000(m^2) *0.68* 5.67* 10^-8* (290^4)

= 3.82W

7 0
4 years ago
lines of latitude a. run from north to south b.start greenwitch,greenland c. are parallel to the equator d.indicate magnetic dec
kenny6666 [7]
The answer is C.
they run east to west which makes them parallel to the equator and they measure distances north and south. 
I hope this helps.
4 0
4 years ago
Read 2 more answers
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