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loris [4]
3 years ago
10

10 N 30 N 4kg net force = a=f/m=

Physics
1 answer:
ICE Princess25 [194]3 years ago
6 0

Answer:

a=5\ m/s^2

Explanation:

Two forces are 10 N and 30 N. Let us assume that two forces are acting in opposite directions. Net force will be :

F = 30 N - 10 N = 20 N

Now,

F = ma

⇒ a = F/m

So,

a=\dfrac{20}{4}\\\\a=5\ m/s^2

So, the acceleration of the object is 5\ m/s^2.

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How much work is done in holding a 20 N sack of potatoes while waiting in line at the
Yuki888 [10]

Answer: A

Explanation:

honestly, it sounded the best

8 0
2 years ago
If you weigh 690 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun an
lana [24]

Answer:

Explanation:

Given that,

Mass of star M(star) = 1.99×10^30kg

Gravitational constant G

G = 6.67×10^−11 N⋅m²/kg²

Diameter d = 25km

d = 25,000m

R = d/2 = 25,000/2

R = 12,500m

Weight w = 690N

Then, the person mass which is constant can be determined using

W =mg

m = W/g

m = 690/9.81

m = 70.34kg

The acceleration due to gravity on the surface of the neutron star is can be determined using

g(star) = GM(star)/R²

g(star) = 6.67×10^-11 × 1.99×10^30 / 12500²

g (star) = 8.49 × 10¹¹ m/s²

Then, the person weight on neutron star is

W = mg

Mass is constant, m = 70.34kg

W = 70.34 × 8.49 × 10¹¹

W = 5.98 × 10¹³ N

The weight of the person on neutron star is 5.98 × 10¹³ N

5 0
3 years ago
A basketball player grabbing a rebound jumps 76.0 cm vertically. How much total time (ascent and descent) does the player spend
Viefleur [7K]

a) we can answer the first part of this by recognizing the player rises 0.76m, reaches the apex of motion, and then falls back to the ground we can ask how

long it takes to fall 0.13 m from rest: dist = 1/2 gt^2 or t=sqrt[2d/g] t=0.175

s this is the time to fall from the top; it would take the same time to travel

upward the final 0.13 m, so the total time spent in the upper 0.15 m is 2x0.175

= 0.35s

b) there are a couple of ways of finding thetime it takes to travel the bottom 0.13m first way: we can use d=1/2gt^2 twice

to solve this problem the time it takes to fall the final 0.13 m is: time it

takes to fall 0.76 m - time it takes to fall 0.63 m t = sqrt[2d/g] = 0.399 s to

fall 0.76 m, and this equation yields it takes 0.359 s to fall 0.63 m, so it

takes 0.04 s to fall the final 0.13 m. The total time spent in the lower 0.13 m

is then twice this, or 0.08s

5 0
3 years ago
Read 2 more answers
Identify the object that has the largest moment from the list of objects given below.
Luda [366]

Answer:

A fired bullet

Explanation:

A fired bullet is faster than the speed of sound

7 0
2 years ago
Could you explain to me how the soccer collects kinetic energy when its kicked?
aniked [119]
FOR THAT YOU NEED TO UNDERSTAND WHAT ACTUALLY KINETIC ENERGY IS.
It is a form of energy which is caused due to motion, when the ball is kicked, it is send into motion thus it gains kinetic energy, how come energy came from ? as you have already read this ENERGY MASS CANT BE CREATED OR DESTROYED. In this scenario the energy is being transferred by the football player into the ball which appears as the kinetic energy of the ball... that's how it works
8 0
3 years ago
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