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3 years ago

Why are earbud wires for an mp3 player coated with plastic

Physics

2 answers:

andriy [413]3 years ago

7 0

The naked wires are dangerous, so the plastic coating insulates and protects the wires :)

saw5 [17]3 years ago

6 0

2) they add the insulation to better the durability or the earbuds

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Which has more potential energy: an eraser 2 feet above your head or a brick 2 feet above your head?

Vika [28.1K]

The brick because it has more mass which means more potential energy

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3 years ago

If you had a mass of 44 g and a volume of 40.5ml what is the density

klio [65]

Here, We know, Density = Mass / Volume
Here, mass = 44 g
volume = 40.5 ml = 40.5 cm³

Substitute their values,
d = 44 / 40.5
d = 1.086 g/cm³

In short, Your Answer would be 1.086 g/cm³

Hope this helps!

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3 years ago

A radar used to detect the presence of aircraft receives a pulse that has reflected off an object 5 ✕ 10−5 s after it was transm

Sunny_sXe [5.5K]

Answer:

7500 m

Explanation:

The radar emits an electromagnetic wave that travels towards the object and then it is reflected back to the radar.

We can call L the distance between the radar and the object; this means that the electromagnetic wave travels twice this distance, so

d = 2L

In a time of

$t=5\cdot 10^{-5}s$

Electromagnetic waves travel in a vacuum at the speed of light, which is equal to

$c=3.0\cdot 10^8 m/s$

Since the electromagnetic wave travels with constant speed, we can use the equation for uniform motion ,so:

$d=vt$ (1)

where

$v=c=3.0\cdot 10^8 m/s$

$t=5\cdot 10^{-5}s$

$d=2L$ , where L is the distance between the radar and the object

Re-arranging eq(1) and substituting, we find L:

$L=\frac{vt}{2}=\frac{(3.0\cdot 10^8)(5\cdot 10^{-5})}{2}=7500 m$

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4 years ago

An ideal parallel plate capacitor with a cross-sectional area of 0.4 cm2 contains a dielectric with a dielectric constant of 4 a

Mrrafil [7]

Answer: $283.2\times 10^{-9}\ nC$

Explanation:

Given

Cross-sectional area $A=0.4\ cm^2$

Dielectric constant $k=4$

Dielectric strength $E=2\times 10^8\ V/m$

Distance between capacitors $d=5\ mm$

Maximum charge that can be stored before dielectric breakdown is given by

$\Rightarrow Q=CV\\\\\Rightarrow Q=\dfrac{k\epsilon_oA}{d}\cdot (Ed)\quad\quad [V=E\cdot d]\\\\\Rightarrow Q=k\epsilon_oAE\\\\\Rightarrow Q=4\times 8.85\times 10^{-12}\times 0.4\times 10^{-4}\times 2\times 10^8\\\\\Rightarrow Q=28.32\times 10^{-8}\\\\\Rightarrow Q=283.2\times 10^{-9}\ nC$

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3 years ago

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Travka [436]

It's called a hypothesis :D

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4 years ago

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