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Anastasy [175]
3 years ago
5

A rocket travels 600m while being accelerated uniformly from rest at a rate

Physics
1 answer:
Anuta_ua [19.1K]3 years ago
7 0

The final velocity of the rocket is 77.5 m/s in the direction of motion

Explanation:

The given in the problem is:

1. The  rocket travels 600 m

2. It starts from rest

3. It is being accelerated uniformly at rate 5 m/s²

We need to find the final velocity

We can use this rule to solve the problem

→ v² = u² + 2 a s

where v is the final velocity, u is the initial velocity, s is the distance

and a is the acceleration

→ u = 0 m/s , a = 5 m/s² , s = 600 m

Substitute these values in the rule above

→ v² = (0)² + 2 (5)(600)

→ v² = 6000

Take √ for both sides

→ v = 77.5 m/s in the direction of motion

The final velocity of the rocket is 77.5 m/s in the direction of motion

Learn more:

You can learn more about the change in velocity in brainly.com/question/12639288

#LearnwithBrainly

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The mass of a ship before launch is 55,000 metric tons. The ship is launched down a ramp and drops a total of 10 vertical meters
skelet666 [1.2K]

Answer:

ΔT = 17.11 °C

Explanation:

In this case, we have a ship standing on a place with a given mass and it's about to be launched to a lock containing water.

At first, before launch, the ship has a potential energy, and when the ship hits the water after being launched, this potential energy is transformed into kinetic energy.

So, let's calculate first the potential energy of the ship:

E = mgh   (1)

We have the mass, gravity and height, so we need to replace the given data here. Before we do that, let's remember to use the correct units. A ton is 1000 kg, so replacing and converting we have:

E = (55000 ton * 1000 kg/ton) * (9.8 m/s²) * 10 m

E = 5.39x10⁹ J

Now this energy will be the same when the ship hits the water, only that is kinetic energy that will result in the rise of temperature. To get this rise we use the following expression:

E = m * C * ΔT   (2)

We have the energy, the mass of water (assuming density of water as 1 kg/m³) and the specific heat, so, replacing in (2) and solving for ΔT we have:

ΔT = E / m * C    (3)

ΔT = 5.39x10⁹ / 4200 * 75000

<h2>ΔT = 17.11 °C</h2>

Hope this helps

5 0
3 years ago
Two rocks are at the top of a building. Rock 1 is dropped from rest while Rock 2 is thrown horizontaly at a velocity of 5 ms.
LuckyWell [14K]

Answer:

I'm pretty sure the answer is 0 m/s²

Explanation:

The horizontal velocity of the second rock is 5 m/s, so if we pretend air resistance doesn't exist, it will maintain that horizontal velocity, meaning that there is no horizontal acceleration.

7 0
3 years ago
John goes grocery shopping with his mother. His job is to push the cart. The cart is
lora16 [44]

Answer:

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Explanation:

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PLEASE HURRY Which of the following measurements is a measurement of velocity?
madreJ [45]

Answer:

C) 350 m/s N

Explanation:

Velocity is measured in miles per hour or metres per second.

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3 years ago
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Delicious77 [7]

Answer:

1. Luminosity

2.Apparent brightness

Explanation:

There are two factors on which brightness of star appear to be in the sky

The two factors are

1. Luminosity

2.Apparent brightness

1.Luminosity :It is defined as the total energy emitted by the object in a given time.Luminosity vary with the distance of observer from the star.Luminosity is a intrinsic property which depends on the fundamental chemical composition and structure of the  material.Luminosity is depends on the size of star.Lager the star luminosity will be more.

2.Apparent brightness: It is defined as how bright a star appears from an observer on the earth and the amount of starlight reaching the earth.if the distance is large then the brightness decreases.When the distance of star from us small then the   brightness of star increases.Distance is inversely proportional to brightness of the star.

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