The final velocity of the rocket is 77.5 m/s in the direction of motion
Explanation:
The given in the problem is:
1. The rocket travels 600 m
2. It starts from rest
3. It is being accelerated uniformly at rate 5 m/s²
We need to find the final velocity
We can use this rule to solve the problem
→ v² = u² + 2 a s
where v is the final velocity, u is the initial velocity, s is the distance
and a is the acceleration
→ u = 0 m/s , a = 5 m/s² , s = 600 m
Substitute these values in the rule above
→ v² = (0)² + 2 (5)(600)
→ v² = 6000
Take √ for both sides
→ v = 77.5 m/s in the direction of motion
The final velocity of the rocket is 77.5 m/s in the direction of motion
Learn more:
You can learn more about the change in velocity in brainly.com/question/12639288
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