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3 years ago

A rocket travels 600m while being accelerated uniformly from rest at a rate

Physics

1 answer:

Anuta_ua [19.1K]3 years ago

7 0

The final velocity of the rocket is 77.5 m/s in the direction of motion

Explanation:

The given in the problem is:

1. The rocket travels 600 m

2. It starts from rest

3. It is being accelerated uniformly at rate 5 m/s²

We need to find the final velocity

We can use this rule to solve the problem

→ v² = u² + 2 a s

where v is the final velocity, u is the initial velocity, s is the distance

and a is the acceleration

→ u = 0 m/s , a = 5 m/s² , s = 600 m

Substitute these values in the rule above

→ v² = (0)² + 2 (5)(600)

→ v² = 6000

Take √ for both sides

→ v = 77.5 m/s in the direction of motion

The final velocity of the rocket is 77.5 m/s in the direction of motion

Learn more:

You can learn more about the change in velocity in brainly.com/question/12639288

#LearnwithBrainly

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A boy throws rocks with an initial velocity of 12m/s [down] from a 20 m bridge into a river. Consider the river to be at a heigh

stira [4]

Answer:

Please find attached the Velocity-Time graph, the Displacement-Time graph and the combined Velocity/Displacement-Time graph, created with Microsoft Excel

Explanation:

The given parameters are;

The initial velocity with which the boy throws the rock, u = 12 m/s

The direction in which he throws the rock = Down

The height from which the rock was thrown, h = 20 m

The height at which the river is located = 0 m

The kinematic equation of motion, of the rock can be given as follows;

h = u·t + 1/2·g·t²

Where;

t = The time of motion of the rock

g = The acceleration due to gravity = 9.8 m/s²

h = The height from which the rock is thrown = 20 m

Substituting the known values into given equation, we get;

20 = 12·t + 1/2·9.8·t² = 12·t + 4.9·t²

4.9·t² + 12·t - 20 = 0

t = (-12 ± √(12² - 4×4.9×(-20)))/(2 × 4.9) = (-12 ± √(242))/(9.8)

t ≈ -3.587 seconds or t ≈ 1.138 seconds

Attached please find the Velocity-Time graph, the Displacement-Time graph and the combined Velocity/Displacement-Time graph, created with Microsoft Excel.

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3 years ago

A ball on the end of a string is rotating with constant speed in a horizontal plane. When the ball is moving North it is located

joja [24]

Answer:

Option A

Explanation:

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The right hand rule says that if you hold the axis with your right hand and rotate the fingers in the direction of motion of the rotating body then your thumb will point the direction of the angular velocity.

Following this, curving the fingers in such a way that they depict motion from the east to north, we can see that our thumb will point upwards. This makes the direction of the angular velocity at that point in time to be up

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3 years ago

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pochemuha

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Read 2 more answers

Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the eq

gayaneshka [121]

Answer:

The volume is decreasing at 160 cm³/min

Explanation:

Given;

Boyle's law, PV = C

where;

P is pressure of the gas

V is volume of the gas

C is constant

Differentiate this equation using product rule:

$V\frac{dp}{dt} +P\frac{dv}{dt} = \frac{d(C)}{dt}$

Given;

$\frac{dP}{dt}$ (increasing pressure rate of the gas) = 40 kPa/min

V (volume of the gas) = 600 cm³

P (pressure of the gas) = 150 kPa

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(600 x 40) + (150 x $\frac{dv}{dt}$ ) = 0

$\frac{dv}{dt} = -\frac{(600*40)}{150} = -160 \ cm^3/min$

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