1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
allsm [11]
4 years ago
6

A __________ provides a visual summary of the improvements that a data mining project provides on a binary classification proble

m compared to a random guess
a. Pareto chart
b. lift chart
c. Gantt chart histogram
Physics
1 answer:
babymother [125]4 years ago
5 0

Answer:

Option (B)

Explanation:

A lift chart usually refers to a graphical representation that is mainly used in order to improve the drawbacks of a mining model by making a comparison with any random guess, and also helps in determining the changes that occur in terms of lift scores.

It describes the binary classification of the problems associated with the mining activity. This type of chart is commonly used to differentiate the lift scores for a variety of models, and picking the best one out of all.

Thus, the correct answer is option (B).

You might be interested in
What kind of movement does the heat within the core and mantle directly generate?
cluponka [151]
Heat within the earth generates convection currents in the mantle. Convection currents represent the circular motion of molten rocks in the mantle driven by heat from the core. This circular motion is what drives the plates and creates the theory of plate tectonics which states that the earth crust is divided into plates that float on the semi-molten mantle below. 
7 0
3 years ago
The application of knowledge to solve practical problems is known as.
igomit [66]
PEMDAS which means Parenthesis, Exponet, Multiplication, Division, Addition, and Subtraction.
3 0
3 years ago
What is the gravitational force between two masses of 15kg each, when their centers are 0.25m? Could you detect this force with
Lunna [17]
Well I don't know !
Let's work it out.

The gravitational force between two objects is

                     F  =  G  ·  M₁·M₂ / R²     .

'G'    is the 'universal gravitational constant'.  We could look it up. 
'M₁'  is the mass of one object
'M₂'  is the mass of the other object 
'R'    is the distance between their centers. 

It looks complicated, but stay with me.  We can do this !
We know all the numbers, so we can calculate the force.

'G'    is  6.67 x 10⁻¹¹ newton·meter² / kg²   (I looked it up.  You're welcome.)
'M₁'  is  15 kg
'M₂'  is  15 kg 
'R'    is  0.25 meter.

Now it's time to pluggum in.

       F  =  G  ·  M₁·M₂ / R²

           = (6.67 x 10⁻¹¹  newton·meter² / kg²) · (15 kg) · (15 kg)  /  (0.25 m²)

           = (6.67 x 10⁻¹¹  ·  15  ·  15 / 0.0625)  N·m²·kg·kg / kg²·m²

           =      2.4 x 10⁻⁷  Newton  .

That a force equivalent to about  0.00000086  of an ounce.
This is the answer to part-a.

Concerning the answer to part-b ...
Personally, I could not detect this force, no matter what kind of equipment
I had. But I am just a poor schlepper engineer, educated in the last Century,
living out my days on Brainly and getting my kicks from YouTube videos. 
I am not pushing the box to the envelope, or thinking outside the cutting
edge ... whatever.
I am sure there are people ... I can't name them, because they keep a
low profile, they stay under the radar, they don't attract a lot of media
attention, their work is not as newsworthy as the Kardashians, and plus,
they seldom call me or write to me ... but I know in my bones that there
are people who have measured the speed of light to NINE significant figures,
aimed a spacecraft accurately enough to take close-up pix of Pluto ten years
later, and detected gravity waves from massive blobs that merged 13 billion
years ago, and I tell you that YES !  THESE guys could detect and measure
a force of  0.86 micro-ounce if they felt like it !
4 0
3 years ago
At what height from the surface of the earth does the value of acceleration due to gravity be 2.45 m/s square where the radius o
Citrus2011 [14]

Answer:

Explanation: RADIUS OF EARTH = 6400X1000m =

ACC DUE GRAVITY ABOVE SURFACE OF EARTH = g' =2.45 m/s^2

ACC DUE GRAVITY ON SURFACE OF EARTH =g= 9.8 m/s^2

A/C TO FORmULA

g'/g=1-2h/Re

g'/g +2h/Re = 1

2h/Re =1- g'/g

2h= (1- g'/g)Re

2h=(1-2.45 /9.8)

6400X1000

2h = (0.75)6400X1000

2h = 4800000

h= 2400000

m

3 0
2 years ago
Which of the following is not a possible environmental effect of acid rain?
grin007 [14]

Answer:

but where are the options?

8 0
2 years ago
Other questions:
  • How would you explain social control to someone who has no idea about our society?
    9·1 answer
  • You are looking out the window of a spaceship and notice another spaceship go by. Which of the following could be moving? Select
    8·1 answer
  • Describe the motion of charges from one terminal of a battery to the other through a flashlight.
    5·1 answer
  • Which is the phase change in which a substance changes from a gas to liquid?
    11·1 answer
  • What two forces are balanced in what we call gravitational equilibrium?
    10·1 answer
  • Two plane mirrors are facing each other. They are parallel, 6 cm apart, and 24 cm in length, as the drawing indicates. A laser b
    12·2 answers
  • 8. A car moved 20 km East and 70 km West.<br> What is the distance?
    7·2 answers
  • A kid drives 4 miles to the mall. If the speed limit is 45 miles/hr and the kid makes the trip in .03 hours. Is the kid breaking
    6·1 answer
  • What could you do to increase the electric potential energy between two
    13·1 answer
  • Could gold be made from other elements?
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!