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allsm [11]
3 years ago
6

A __________ provides a visual summary of the improvements that a data mining project provides on a binary classification proble

m compared to a random guess
a. Pareto chart
b. lift chart
c. Gantt chart histogram
Physics
1 answer:
babymother [125]3 years ago
5 0

Answer:

Option (B)

Explanation:

A lift chart usually refers to a graphical representation that is mainly used in order to improve the drawbacks of a mining model by making a comparison with any random guess, and also helps in determining the changes that occur in terms of lift scores.

It describes the binary classification of the problems associated with the mining activity. This type of chart is commonly used to differentiate the lift scores for a variety of models, and picking the best one out of all.

Thus, the correct answer is option (B).

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Calculate the displacement of a car waxing point of 11 m to the final positions of 4 meters
Nastasia [14]

Answer:

-7 m

Explanation:

Displacement is a vector connecting the initial position of motion of an object to its final position.

For the car in this problem, we have:

- Initial position: + 11 m

- Final position: + 4 m

Therefore, the vector displacement will be:

d = +4 - (+11) = -7 m

Which means:

- Magnitude of 7 m

- Negative direction

3 0
3 years ago
At launch a rocket ship weighs 4.5 million pounds. When it is launched from rest, it takes 8.00 s to reach 161 km/h; at the end
SpyIntel [72]

Answer:

5.590278\ m/s^2

7.74038461538\ m/s^2

178.888896 m

12790.56 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{161}{3.6}-0}{8}\\\Rightarrow a=5.590278\ m/s^2

The acceleration is 5.590278\ m/s^2

v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{1610}{3.6}-\dfrac{161}{3.6}}{60-8}\\\Rightarrow a=7.74038461538\ m/s^2

The acceleration is 7.74038461538\ m/s^2

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 5.590278\times 8^2\\\Rightarrow s=178.888896\ m

Distance traveled in the first 8 seconds is 178.888896 m

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=\dfrac{161}{3.6}\times 52+\dfrac{1}{2}\times 7.74038461538\times 52^2\\\Rightarrow s=12790.56\ m

Distance traveled during 8-60 second interval is 12790.56 m

6 0
3 years ago
Alicia está a punto de perder su bus. En un desesperado intento, corre a una velocidad constante de 5 m/s. Cuando está a 15 m de
pochemuha

Answer:

Si logra alcanzar el bus.

Explanation:

Para poder solucionar este problema debemos de tener en cuenta que Alicia corre a velocidad constante para poder alcanzar el bus. La formula de la cinematica que tiene en cuenta la velocidad constante es la siguiente:

x_{f} = x_{o}+(v*t)

donde:

Xf = Ubicacion del punto donde se encuentra el bus [m]

Xo = Ubicacion desde donde esta Alicia [m]

v = velocidad constante = 5 [m/s]

t = tiempo [s]

Xf - Xo = 15 [m]

15 = 5*t

t = 3 [s]

Ahora con el tiempo podemos encontrar la velocidad del bus por medio de la siguiente ecuacion de cinematica para la aceleracion constante:

v_{f} = v_{i}+(a*t)

donde:

Vf = velocidad del bus despues de los 3 [s]

Vi = velocidad inicial = 0

a = aceleracion = 0.5 [m/s^2]

Vf = 0 + (0.5*3)

Vf = 1.5 [m/s]

La velocidad del bus es menor que la velocidad de Alicia, por ende Alicia alcanzara el bus.

7 0
3 years ago
A basketball has a mass of 601 g. Moving to the right and heading downward at an angle of 29 degree to the vertical, it hits the
olga55 [171]

Answer:

Change in momentum, \Delta p=6.3\ kg-m/s

Explanation:

It is given that,

Mass of the basketball, m = 601 g = 0.601 kg

The basketball makes an angle of 29 degrees to the vertical, it hits the floor with a speed, v = 6 m/s

It bounces up with the same speed, again moving to the right at an angle of 29 degree to the vertical. We need to find the change in momentum. It is given by :

\Delta p=mv\ cos\theta-(-mv\ cos\theta)

\Delta p=2mv\ cos\theta

\Delta p=2\times 0.601\times 6\times \ cos(29)

\Delta p=6.3\ kg-m/s

So, the change in momentum of the basketball is 6.3 kg-m/s. Hence, this is the required solution.

6 0
3 years ago
A2 kg block is accelerating at the rate of 5 m/s² while being acted on by two forces. One of the forces equals 30 N, 0°. What ar
Mademuasel [1]

Answer:

20 [N], in the opposite direction of the first force.

Explanation:

We know that newton's second law stipulates that the sum of forces on a body must be equal to the product of mass by acceleration.

SumF = m*a\\30 + F = 2*5\\F = 30 - (2*5)\\F = - 20 [N]

The negative sign means that the other force acting on the body must be in the opposite direction to the force of 30 [N]

6 0
3 years ago
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