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allsm [11]
4 years ago
6

A __________ provides a visual summary of the improvements that a data mining project provides on a binary classification proble

m compared to a random guess
a. Pareto chart
b. lift chart
c. Gantt chart histogram
Physics
1 answer:
babymother [125]4 years ago
5 0

Answer:

Option (B)

Explanation:

A lift chart usually refers to a graphical representation that is mainly used in order to improve the drawbacks of a mining model by making a comparison with any random guess, and also helps in determining the changes that occur in terms of lift scores.

It describes the binary classification of the problems associated with the mining activity. This type of chart is commonly used to differentiate the lift scores for a variety of models, and picking the best one out of all.

Thus, the correct answer is option (B).

You might be interested in
Two cars collide inelastically and stick together after the collision. Before the collision, the magnitudes of their momenta are
slavikrds [6]

Answer:

The correct answer is

p = p₁ + p₂

Explanation:

Newton's second law states that force = the change of momentum produced therefore since the collision is inelstic then the change of momentum of each car is p₁ and  p₂ and the force of the collition is proportional to p₁ + p₂ that is

F ∝ p₁ + p₂ and since force is directly proportional to p we have

p = p₁ + p₂

7 0
4 years ago
A jet aircraft with mass of 658,055 kilograms is flying straight downward. At an instant the plane's engine is producing an down
sdas [7]

Answer:

The acceleration of the plane is 10.93 m/s² at that instant.

Explanation:

Given:

Mass of aircraft, m=658055\textrm{ kg}

Downward thrust produced, F=1484732.5\textrm{ N}

Upward resistance force by air, F_{R}=740492.6\textrm{ N}

Weight of the aircraft acting donward, W=mg=658055\times 9.8=6448939\textrm{ N}

According to Newton's second law, net force acting on an object is equal to the product of mass and its acceleration.

Here, the net force is given as the difference of downward forces and upward forces.

F_{net}= F+W-F_{R}\\ F_{net}=1484732.5+6448939-740492.6=7193178.9\textrm{ N}

Now,

F_{net}=ma\\7193178.9=658055a\\a=\frac{7193178.9}{658055}=10.93\textrm{ }m/s^{2}

Therefore, the acceleration of the plane is 10.93 m/s² at that instant.

3 0
4 years ago
Match each feature related to the process of seafloor spreading with its location on the diagram
nikklg [1K]

Answer:

Seafloor spreading is a geological process that occurs in the ocean. It is occurs due to divergent plate tectonics. As, lithospheric plates of the ocean moves away from each other, the heat from the mantle liberates as convection currents that decreases the density of the crust. The less dense material rises, resulting the elevation of the seafloor, which is called as sea floor spreading.

Explanation:

4 0
3 years ago
If you were standing at sea level measuring the air pressure, you would actually be measuring the air's _____.
shusha [124]

Answer:

Weight of air per unit area is pressure due to atmosphere. So here correct answer is Weight

Explanation:

As we know that air pressure is given by

P = \frac{Force}{Area}

now we know that force here due to air is due to the weight of the air

so here in order to calculate the weight we will have

Weight = mg

Weight = \rho Ah g

here we know that

Ah = volume of air above the point where pressure is to be calculated

now from above formula we have

P = \frac{\rho AH g}{A} = \rho g h

so here we can say that pressure is due to weight of air

3 0
3 years ago
A block weighing 87.0 N rests on a plane inclined at 24.1° to the horizontal. The coefficient of the static and kinetic friction
Tom [10]

Answer:

15.7 N

Explanation:

Draw a free body diagram.  The block has four forces acting on it.  Gravity pulling down, normal force pushing perpendicular to the plane, friction pointing up the plane, and applied force F pushing up the plane.

Sum of the forces normal to the plane:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Sum of the forces parallel to the plane:

∑F = ma

Nμ + F − mg sin θ = 0

F = mg sin θ − Nμ

Substituting:

F = mg sin θ − mgμ cos θ

F = mg (sin θ − μ cos θ)

Given mg = 87.0 N, θ = 24.1°, and μ = 0.25 (because the block is not moving):

F = 87.0 N (sin 24.1° − 0.25 cos 24.1°)

F = 15.7 N

4 0
3 years ago
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