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Ludmilka [50]
3 years ago
11

Explain how the gas laws apply to the act of breathing. Describe the changes that occur in each step of the process in terms of

the pressure, volume, temperature, and moles of gas present for each step, identify which variables are constant, and which are changing name the gas law or gas laws that apply to the process create and solve a sample calculation using realistic values of pressure, temperature, amount of gas, and volume. Please HELP!
Physics
1 answer:
MrRa [10]3 years ago
4 0
<span>When you in inhale, you move your diaphragm down increasing the volume of the cavity in your ribs (its called pleural cavity). This lowers the pressure inside your lungs. When the pressure in your lungs is less than the atmospheric pressure, air draws inwards. Ideal gas law: PV=nRT -> assume nRT are constant for our purposes. then we allow one system to be equal to the same system at different conditions, thus: P1V1=P2V2 (Boyles Law) assume P1=1 atm and V1=1 L (keeping the numbers simple to avoid confusion). when the V is increased (for example say doubled) V2=2 L, then: (1 atm)*(1 L)=P2*(2 L) -> P2=0.5 atm The pressure was decreased. Apply the same logic for exhalation.</span>
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PLEASE HELP ASAP!!!!!
Igoryamba

While falling, both the sheet of paper and the paper ball experience air resistance. But the surface area of the sheet is much more than that of the spherical ball. And air resistance varies directly with surface area. Hence the sheet experiences more air resistance than the ball and it falls more slowly than the paper ball.

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8 0
3 years ago
1) The unit of power is
miss Akunina [59]

Answer:

1) the unit of power is A.Watt

2)100J=50W

100=50s

divide both sides by 50s

S=2s(A)

4 0
3 years ago
A dragster starts with zero velocity and completes a 404.5 m (0.2528 mile) run in 4.922 s. If the car had a constant acceleratio
KIM [24]

Answer:

a. a=33.34ms⁻², V=164.4m/s

Explanation:

Since the dragster started with zero velocity, de determine the acceleration using of the equations of motion.

Below are the data given

Distance, s=404.5m,

time taken,t=4.922secs

Using the equation

S=ut+1/2at²

where u is the initial velocity and u=0

Making the acceleration the subject of the formula, we arrive at

a=2s/t²

a=(2*404.5)/4.922²

a=33.34ms⁻².

To determine the velocity, we use

V=u+at

V=0+33.34ms⁻² *4.922sec

V=164.4m/s

5 0
3 years ago
Read 2 more answers
35 miles North 6 feet down 136 MB 85 km SE
pantera1 [17]
The answer is 133 Se
4 0
3 years ago
Read 2 more answers
Example of energy transfer from potential to kinetic and back
Alex_Xolod [135]

Swimmer and Divers. The Potential energy is transferred into Kinetic energy, and allows the diver to submerge into the water. The Kinetic energy then allows the diver to submerge and dive into the water. Potential energy however, is needed to allow the diver to get back out of the water after diving to get up and go and dive again, and then the Kinetic energy is transferred back to Potential energy to repeat the process.

Hope :) -Emilie Xo this is right and it helps! Xo

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3 years ago
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