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Taya2010 [7]
3 years ago
10

What is the percent of copper in CuS?

Chemistry
1 answer:
bonufazy [111]3 years ago
7 0

Answer:

Element Symbol Mass Percent

Cuprum Cu 66.464%

Sulfur S 33.537%

Explanation:

I got this out of my module, sorry if it's wrong but i am pretty sure 97% this is correct!

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Select the correct answer. Which statement is true for a heating curve?
Anon25 [30]

Answer:

OB

Explanation:

tht is correct make me brainliest

8 0
3 years ago
An object has a mass of 18 grams and its volume is 2cm3 Calculate density:​
Natalka [10]

Answer:

9g/cm^3 is the density

Explanation:

P = m/V

P = 18/2 = 9g/cm^3

(This is more of a physics question than chem btw)

6 0
2 years ago
Read 2 more answers
Stomach acid is approximately 0.10 M HCl. How many mL of stomach acid can be neutralized by one regular antacid tablet that cont
Radda [10]

Answer:

100 mL

Explanation:

The reaction that takes place is:

  • CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

First we <u>convert 500 mg of CaCO₃ into mmoles</u>, using its <em>molar mass</em>:

  • 500 mg ÷ 100 mg/mmol = 5 mmol CaCO₃

Then we <u>convert 5 mmoles of CaCO₃ into HCl mmoles</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:

  • 5 mmol CaCO₃ * \frac{2mmolHCl}{1mmolCaCO_3} = 10 mmol HCl

Finally we <u>calculate the volume of a 0.10 M HCl solution (such as stomach acid) that would contain 10 mmoles</u>:

  • 10 mmol / 0.10 M = 100 mL
7 0
3 years ago
What is an electrolytic cell?
Verizon [17]

Answer:

Hey mate here is your answer in short

Explanation:

An electrolytic cell uses electrical energy to drive a non-spontaneous redox reaction. An electrolytic cell is a kind of electrochemical cell. It is often used to decompose chemical compounds, in a process called electrolysis—the Greek word lysis means to break up.

hope it helps you ❣️

4 0
3 years ago
Read 2 more answers
In an experiment, 16.8 g of k2so4 was dissolved in 1.00 kg of water to make a solution. the freezing point of the solution was m
Mashutka [201]
Answer is: V<span>an't Hoff factor (i) for this solution is 2,26.
</span>Change in freezing point from pure solvent to solution: ΔT =i · Kf · m.
<span>Kf - molal freezing-point depression constant for water is 1,86°C/m.
</span>m -  molality, moles of solute per kilogram of solvent.
n(K₂SO₄) = 16,8 g ÷ 174,25 g/mol
n(K₂SO₄) = 0,096 mol.
m(K₂SO₄) = 0,096 mol/kg.
ΔT = 0,405°C.
i = 0,405 ÷ (1,86 · 0,096)
i = 2,26.

8 0
3 years ago
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