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3 years ago

What is the best way to combine these sentences? The frogs front feet have 4 toes. Its back feet have 5 toes

Chemistry

2 answers:

mrs_skeptik [129]3 years ago

8 0

Answer:

The frog has 4 toes on each foot in the front, and 5 toes on each foot in the back.

Explanation:

son4ous [18]3 years ago

5 0

The frog has 9 toes.

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Dolphins communicate using compression waves (longitudinal waves). Some of the sounds dolphins make are outside the range of hu

Gre4nikov [31]

I believe the answer is A. make a softer sound because the shark will not hear the softer signal.

I say this becasue "Some of the sounds dolphins make are outside the range of human hearing." So that means the the dolphins speak at a higher wavelength then us humans and we can't hear it so they could use that to their advantage and speak at a height wavelength to each other when sharks are near.

I could be wrong, but I think the answer is A.

8 0

3 years ago

Read 2 more answers

What volume of 0.4567 m h2so4 is required to neutralize 30.00 ml of 0.3210 m naoh?

sertanlavr [38]

Answer is: volume of H₂SO₄ is 42.1 mL.
Chemical reaction: H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.
c(H₂SO₄) = 0,4567 M = 0,4567 mol/L.
V(NaOH) = 30 mL ÷ 1000 mL/L = 0,03 L.
c(NaOH) = 0,321 M = 0,321 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,321 mol/L · 0,030 L.
n(NaOH) = 0,00963 mol.
From chemical reaction: n(H₂SO₄) : n(NaOH) = 1 : 2.
n(H₂SO₄) = 0,01926 mol.
V(H₂SO₄) = n(H₂SO₄) ÷ c(H₂SO₄).
V(H₂SO₄) = 0,01926 mol ÷ 0,4567 mol/L.
V(H₂SO₄) = 0,0421 L = 42,1 mL.

3 0

3 years ago

N2H4 + N2O4 --> N2 + H2O

ahrayia [7]

Answer:

The limiting reagent is N2O4
14,09g

Explanation:

First, we adjust the reaction.

$2N_{2} H_{4}$ + $N_{2} O_{4}$ ⇄ $6N_{2} + 4H_{2}O$

Second, we assume that the participating moles are equal to the stoichiometric ratios because we do not know the amounts of the reagents.

We can determinate what is the limiting reagent comparing of product amounts which can be formed from each reactant.

Using $N_{2} H_{4}$ to form $H_{2}O$

$molH_{2} O = 1mol N_{2} H_{4} } . \frac{4 mol H_{2} O}{2mol N_{2} H_{4} }. \frac{18\frac{g}{mol} H_{2} O}{1mol H_{2} O_} } . \frac{ 1 mol N_{2}H_{4} }{32,04\frac{g}{mol} N_{2} H_{4} }$

$molH_{2} O = 1, 125 mol$

Using $N_{2} O_{4}$ to form $H_{2} O$

$molH_{2} O = 1mol N_{2} O_{4} } . \frac{4 mol H_{2} O}{1mol N_{2} O_{4} }. \frac{18\frac{g}{mol} H_{2} O}{1mol H_{2} O_} } . \frac{ 1 mol N_{2}O_{4} }{92\frac{g}{mol} N_{2} O_{4} }$

$molH_{2} O = 0,783 mol$

The limiting reagent is N2O4, because can produce only 0, 783 mol of H2O.

This is the minimum measure can be formed of each product.

∴ $MassOfH_{2}O = 0,783mol . 18\frac{g}{mol}$

$MassOfH_{2}O = 14,09g$

5 0

3 years ago

The atomic number of beryllium (Be) is 4, and the atomic number of barium (Ba) is 56. Which comparison is best supported by this

Cloud [144]

The answer is b) similar chemical properties but very different atomic numbers

8 0

3 years ago

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Help not sure of the answer would appreciate help

S_A_V [24]

Answer:-

(iv) (i) + (II)

Explanation:-

Hydrogen bonds Occur between Hydrogen and an element with high electronegativity like N or O.

DNA base pairs are arranged such that they are complimentary. Hence hydrogen bonding will occur between both the amide carbonyl and NH2 as well as the amide NH and Nitrogen of the cyclic C=N-C group.

6 0

3 years ago

Read 2 more answers