Please help 10 points!!!

Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e

notsponge [240]

Answer: The concentration of $Sn^{2+}$ in the cell is $9.0\times 10^{-3}M$

Explanation:

We are given:

Oxidation half reaction: $Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-$ $E^o_{Zn^{2+}/Zn}=-0.76V$

Reduction half reaction: $Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)$ $E^o_{Sn^{2+}/Sn}=-0.136V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=-0.136-(-0.76)=0.624V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}$

where,

$E_{cell}$ = electrode potential of the cell = 0.660 V

$E^o_{cell}$ = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

$[Zn^{2+}]=2.5\times 10^{-3}M$

$[Sn^{2+}]$ = ?

Putting values in above equation, we get:

$0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})$

$[Sn^{2+}]=9.0\times 10^{-3}M$

Hence, the concentration of $Sn^{2+}$ ions is $9.0\times 10^{-3}M$

3 0

3 years ago

3. HNO3 + NaHCO3 → NaNO3 + H2O + CO2

Bond [772]

Answer:

hydrogen nitrate + sodium hydrochlorate- sodium nitrate+ water + co2 (acid base reaction)

silver nitrate + calcium chloride - silver chloride+ calcium nitrate ( double displacement reaction)

hydrogen + nitrogen - ammonia gas ( simple contact reaction)

hydrogen peroxide - water + oxygen ( single displacement reaction)

Hope it helps :)

8 0

3 years ago

Why are you so much older on Mercury?

Alinara [238K]

Answer:As you can see from the very different numbers in the boxes above, your age changes (sometimes quite a lot) ... Mercury is the closest planet to the Sun and so has a smaller orbit path – it takes just 88 Earth days

Explanation:

4 0

3 years ago

Read 2 more answers

Please help mee 11-14

Artemon [7]

Answer:

11. A)outward

12. B) inward

13. B) opaque

14. I really don't know (sorry)

Explanation:

7 0

3 years ago

The weak base ionization constant (Kb) for HCO3 is equal to:

hammer [34]

Weak bases are alkaline solution that does not get completely dissociated. The dissociation constant will be the ratio of the concentration of the products to the reactants.

<h3>What is a weak base ionization constant?</h3>

The weak base ionization constant is the equilibrium constant that is given as the division of the products of the ionization to the concentration of the reactants.

The reaction for HCO₃ is given as:

HCO₃⁻ + OH⁻ ⇄ CO₃²⁻ + H₂O

The value of Ka for the given reaction will be:

Ka = [CO₃²⁻][H₂O] ÷ [HCO₃⁻ ][OH⁻]

Therefore, the Ka of the weak carbonic acid is given as the ratio of the concentration of the products to the reactants.

Learn more about the weak ionization constant here:

brainly.com/question/27200344

#SPJ1

8 0

2 years ago