Answer:
The value of the missing equilibrium constant ( of the first equation) is 1.72
Explanation:
First equation: 2A + B ↔ A2B Kc = TO BE DETERMINED
⇒ The equilibrium expression for this equation is written as: [A2B]/[A]²[B]
Second equation: A2B + B ↔ A2B2 Kc= 16.4
⇒ The equilibrium expression is written as: [A2B2]/[A2B][B]
Third equation: 2A + 2B ↔ A2B2 Kc = 28.2
⇒ The equilibrium expression is written as: [A2B2]/ [A]²[B]²
If we add the first to the second equation
2A + B + B ↔ A2B2 the equilibrium constant Kc will be X(16.4)
But the sum of these 2 equations, is the same as the third equation ( 2A + 2B ↔ A2B2) with Kc = 28.2
So this means: 28.2 = X(16.4)
or X = 28.2/16.4
X = 1.72
with X = Kc of the first equation
The value of the missing equilibrium constant ( of the first equation) is 1.72
Answer:
9.57
Explanation:
Given that:
Considering the Henderson- Hasselbalch equation for the calculation of the pOH of the basic buffer solution as:
![pOH=pK_b+log\frac{[conjugate\ acid]}{[base]}](https://tex.z-dn.net/?f=pOH%3DpK_b%2Blog%5Cfrac%7B%5Bconjugate%5C%20acid%5D%7D%7B%5Bbase%5D%7D)
So,
pH + pOH = 14
So, pH = 14 - 4.43 = 9.57
Rough, tan, grainy, and scratchy are some
Answer:
inertia
Explanation:
The principal of inertia explains why objects do not voluntarily change their speed or direction without the influence of an external force. Inertia is not unaffected by other forces in planetary systems such as Earth and is, as such, not really observable on planetary surfaces. This is due to the resistance forces of gravity and friction from both the air and the ground. The drag slows objects down and makes it appear as if a constant force were necessary to keep them in motion.
Answer:
In glucose there are 6 carbon atom, atomic weight carbon is 12, so the molar mass is 72 and the percentage composition of carbon in C6H12O6=(72180)×100%=40% percentage by the mass.
