The threshold frequency of Cesium is 5.2 x 10^14 Hz.
To find the frequency of yellow light, we use the equation:
speed of light = wavelength x frequency
3 x 10^8 = 5.8 x 10^-17 x frequency
frequency = 5.17 x 10^24
This is higher than the threshold frequency of Cesium, thus, electrons will be emitted.
Answer:
products
Explanation:
yeah the answer is product
The answer to question 8 is
Ethanol's Molar Heat of Combustion. ... Heats of combustion are quoted as positive numbers while the enthalpy changes of combustion reactions (ΔH) are quoted as negative numbers, as combustion reactions are always exothermic. Heats of combustion are typically stated in kilojoules per mole (kJ/mol. or kJ mol. -1).
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Answer:
Density, 
Explanation:
Given that,
Mass of marble slab is 38.6 kg or 38600 g
The dimensions of the slab is 23 cm × 17 cm ×4 cm
We know that the density of an object is given in terms of its mass volume as follows :
So, the density of the marble slab is 
Answer:
1.195 M.
Explanation:
- We can calculate the concentration of the stock solution using the relation:
<em>M = (10Pd)/(molar mass).</em>
Where, M is the molarity of H₂SO₄.
P is the percent of H₂SO₄ (P = 40%).
d is the density of H₂SO₄ (d = 1.17 g/mL).
molar mass of H₂SO₄ = 98 g/mol.
∴ M of stock H₂SO₄ = (10Pd)/(molar mass) = (10)(40%)(1.17 g/mL) / (98 g/mol) = 4.78 M.
- We have the role that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.
<em>∴ (MV) before dilution = (MV) after dilution</em>
M before dilution = 4.78 M, V before dilution = 250 mL.
M after dilution = ??? M, V after dilution = 1.0 L = 1000 mL.
∴ M after dilution = (MV) before dilution/(V after dilution) = (4.78 M)(250 mL)/(1000 mL) = 1.195 M.
