4x = (130 - 2x) so x = 65/3
(3y + 40) + (130 -2x) = 180 because the angles are supplementary
plug in x
3y + 40 + 130 - 2(65/3) = 180
so 3y = 95/3
therefore y = 95/6
the multiplication table is displayed in the screenshot (up to 12)
Answer:
AE = 18 units
Step-by-step explanation:
Δ AEB and Δ DEC are similar , then corresponding sides are in proportion, that is
= 
, substitute values
= 
( cross- multiply )
10(2x + 4) = 12(x + 8) ← distribute parenthesis on both sides
20x + 40 = 12x + 96 ( subtract 12x from both sides )
8x + 40 = 96 ( subtract 40 from both sides )
8x = 56 ( divide both sides by 8 )
x = 7
Then
AE = 2x + 4 = 2(7) + 4 = 14 + 4 = 18 units
Answer:
a
Step-by-step explanation:
the equation for a circle centered at orgin is x^2+y^2=r where r is the radius. multiplying, adding, or subtracting any numbers to the x and y components such as the other choices here causes the circle to be translated about the graph.
These are the steps, with their explanations and conclusions:
1) Draw two triangles: ΔRSP and ΔQSP.
2) Since PS is perpendicular to the segment RQ, ∠ RSP and ∠ QSP are equal to 90° (congruent).
3) Since S is the midpoint of the segment RQ, the two segments RS and SQ are congruent.
4) The segment SP is common to both ΔRSP and Δ QSP.
5) You have shown that the two triangles have two pair of equal sides and their angles included also equal, which is the postulate SAS: triangles are congruent if any pair of corresponding sides and their included angles are equal in both triangles.
Then, now you conclude that, since the two triangles are congruent, every pair of corresponding sides are congruent, and so the segments RP and PQ are congruent, which means that the distance from P to R is the same distance from P to Q, i.e. P is equidistant from points R and Q
