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3 years ago

How would you answer this?

Mathematics

1 answer:

horsena [70]3 years ago

4 0

Answer:

Step-by-step explanation:

the range and middle range

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Circle O has an area of 200m^2. Point A and B lie on the circle. Sector AOB has an area of 50m^2. What is the measure of angle A

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The answer is 45 have a good day

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3 years ago

The formula to find the perimeter of a rectangle is: P = 2W + 2L. To solve for " W " in this formula, which steps should be foll

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Since the 2L is not being multiplied or divided, and it's positive, we will subtract it from both sides. Since the W is being multiplied by the 2, we'll also need to divide both sides by 2.

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2 years ago

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30+5y_>4x I need the answer ASAP

Gre4nikov [31]

30+5y_>4x
5y_>4x-30
The answer is: y_>(4/5)x-6

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2 years ago

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3 years ago

Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k

valkas [14]

Answer:

$\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k, the vector projection of B unto a is expressed as $proj_ab = \dfrac{b.a}{||a||^2} * a$

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||² = 130

$proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\$

Hence the projection of b unto a is expressed as $\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

7 0

3 years ago