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ad-work [718]
3 years ago
9

How much work does a student (m = 60 kg) do when he Climb a tower 80 m high?

Physics
1 answer:
gtnhenbr [62]3 years ago
7 0

Answer:

W = 47040  J

Explanation:

Given that,

The mass of a student, m = 60 kg

Height of the tower, h = 80 m

We need to find the work done in climbing the tower. The work done is given by :

W = mgh

So,

W = 60 × 9.8 × 80

W = 47040  J

So, the required work done is 47040  J.

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How did the current change when the circuit was initially closed in Part 2 of this exercise? Explain your answer by referencing
Radda [10]

Answer:

Some current is lost.

Explanation:

Change occur in the current when the circuit was initially closed because in a closed circuit the current moves from the start towards the end of the circuit through various resistors. There is heat produced in the wire when the current flows through the circuit. Due to this heat, some of the current is lost during on his own way. Capacitor is a device used to store an electric charge, having of one or more pairs of conductors separated by an insulator. while on the other hand, electric current is a stream of charged particles, such as electrons moving through conductor or space.

7 0
3 years ago
A monkey climbs vertically on a vine. It’s motion is shown on the following graph of vertical position y vs time t.
Andrew [12]

Answer:

0 m/s

Explanation:

if you look at the graph you will see that where the number 5 is there is a straight line meaning there is no motion.

no movement = no speed or distance, and without anything to calculate your answer has to be zero

7 0
3 years ago
Compare and contrast an earthquake and a tsunami.
Scorpion4ik [409]

Answer:

An earthquake is a trembling movement of the earth's crust. These tremors are generally caused by shifts of the plates that make up the earth's surface. ... A tsunami (pronounced soo-NAHM-ee) is a series of huge waves that occur as the result of a violent underwater disturbance, such as an earthquake or volcanic eruption.

Explanation:

4 0
3 years ago
Students use a stretched elastic band to launch carts of known mass horizontally on a track. The elastic bands exert a force F,
rodikova [14]

Answer:

the correct answer is  E

A graph of the cart's maximum speed squared as a function of x^3

Explanation:

For this exercise let's use Newton's second law

        F = m a

force has the form

        F = k x²

and acceleration is related to velocity

        a = dv / dt

Let's use the chain rule or L'Hospital

        a = dv /dx   dx/dt

        a = dv /dx    v

let's substitute

     k x² = m v dv / dx

     k /m x² dx = v dv

we integrate

     k /m    x³ /3 = v² / 2

     v² = (2k /3m)   x³

This is the expression for the variation of the speed as a function of the position, to make a linear graph realism the changes of variable

      y = v²

     x´ = x³

       y = (2k/3m)  x´

if we graph y vs x 'we have a linear graph whose slope is

      m = 2k / 3m

By reviewing the different answers, the correct answer is  E

4 0
3 years ago
A girl of mass 60 kg throws a ball of mass 0.8 kg against a wall. The ball strikes the wall horizontally with a speed of 11 m/s,
True [87]

Answer:

352 N

Explanation:

From Newton's second law of motion,

F = m(v-u)/t................ Equation 1

Where F = Average force exerted on the wall by the ball, m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball, t = time of contact of the ball with the wall.

From the question,

Assuming: The direction of the initial velocity to be negative

Given: m = 0.8 kg, u = -11 m/s, v = 11 m/s (bounce back with the same speed), t = 0.05 s

Substitute into equation 1

F = 0.8[11-(-11)]/0.05

F = 0.8(11+11)/0.05

F = 0.8(22)/0.05

F = 352 N

Hence the average force = 352 N

5 0
4 years ago
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