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ad-work [718]
3 years ago
9

How much work does a student (m = 60 kg) do when he Climb a tower 80 m high?

Physics
1 answer:
gtnhenbr [62]3 years ago
7 0

Answer:

W = 47040  J

Explanation:

Given that,

The mass of a student, m = 60 kg

Height of the tower, h = 80 m

We need to find the work done in climbing the tower. The work done is given by :

W = mgh

So,

W = 60 × 9.8 × 80

W = 47040  J

So, the required work done is 47040  J.

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A glass rod is rubbed with nylon. The rod is then brought close to the metal knob of an electroscope. A person's finger briefly
qwelly [4]

Answer:

On removal to the glass rod the leaves of the electroscope will disperse away under the influence of the positive charge due to deficiency of electrons.

Explanation:

When a glass rod is rubbed against a nylon then the electrons from the surface of the glass rod get transferred to the nylon piece and as a result the glass rod attains positive electrostatic charge.

When this positively charged rod is brought close to the knob of an electroscope then the electrons from that metallic of the electroscope feel attraction and move toward the glass rod get concentrated on the knob.

  • In this situation when any of our body part comes in direct contact to the knob these static concentrated charges get a path to flow from high concentration to a lower concentration under the influence of the electrostatic force of the rod.
  • So these charges flow into our body from the knob.
  • Our body acts as a reservoir for the charges on the metallic knob.
  • Now after the electrons form the knob are transferred to the person's body the electroscope becomes electron deficient and hence positively charged.
  • So now, on removal to the glass rod the leaves of the electroscope will disperse away under the influence of the positive charge.
5 0
4 years ago
If an object looks blue, it reflects ____ waves. Question 4 options: blue red and yellow all but blue all
Masteriza [31]

Answer:

Blue

Explanation:

Because, That object absorbs all colours light waves but des not absorbs Blue. So The blue light is reflected because it is not absorbed

4 0
2 years ago
Neon is compressed from 100 kPa and 24°C to 500 kPa in an isothermal compressor. Determine the change in the specific volume and
trasher [3.6K]

Answer:

ΔV = -0.97 m³/ kg

ΔH = 0 kJ/ kg

Explanation:

<u>To determine the change in the </u><u>specific volume</u><u> we need to </u><u>use the ideal gas law</u><u>:</u>  

PV = RT  

<em>where</em><em> P</em><em>: </em><em>pressure </em><em>of the gas </em><em>V</em><em>: </em><em>volume </em><em>of the gas, </em><em>R</em><em>: i</em><em>deal gas constant</em><em>= 0.4119 kJ/kg.K = 0.4119 kPa.m³/kg.K and </em><em>T</em><em>: </em><em>temperature </em><em>of the gas.</em>

<u />

<u>The </u><u>V₁,</u><u> at a compressed pressure is:</u>

V_{1}= \frac {RT}{P_{1}}      

V_{1}= \frac {0.4119 \frac{kPa\cdot m^{3}}{kg\cdot K} \cdot (24 + 273 K)}{100 kPa}

V_{1}= 1.22 \frac{m^{3}}{kg}

<u>Similarly, the </u><u>V₂</u><u> is:</u>

V_{2}= \frac {RT}{P_{2}}  

V_{2}= \frac {0.4119 \frac{kPa\cdot m^{3}}{kg\cdot K} \cdot (24 + 273 K)}{500 kPa}

V_{2}= 0.25 \frac{m^{3}}{kg}

Now, the change in the specific volume because the compressor is:

V_{2} - V_{1} = 0.25 - 1.22 \frac{m^{3}}{kg}

V_{2} - V_{1} = -0.97 \frac{m^{3}}{kg}  

Finally, to calculate the change in the specific enthalpy, we need to remember that neon is an ideal gas and that is an isothermal process:

\Delta H = C_{p} \cdot \Delta T    

\Delta H = 1.0299 \frac{kJ}{kg \cdot K} \cdot 0    

\Delta H = 0 \frac{kJ}{kg}

Have a nice day!

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vodka [1.7K]
166x5.75= 954.5 meters in 5.75 seconds.
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In hot warter or substant bc hot makes molecues go,s faster then all the rest
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