Hello!
This question requires a model -- you'll have to do that yourself. However, I can explain the steps for the process:
• Chlorophyll absorbs the sun's energy.
• The energy is used to split water molecules into hydrogen and oxygen.
• The oxygen is released from the leaves into the atmosphere.
• The hydrogen and carbon dioxide glucose (food) for plants.
If you have any more questions related to this assignment, please let me know!
Answer:
108.3g
Explanation:
Given parameters:
Volume of solution = 570mm = 0.57L (1000mm = 1L)
Molarity of solution = 2M
Unknown
Mass of MgCl₂
Solution
We first find the number of moles in the given concentration of magnessium chloride using the expression below:
Number of moles of MgCl₂= Molarity x volume = 2 x 0.57 = 1.14moles
Using this known moles, we can the unknown mass of MgCl₂ the technician would require:
Mass of MgCl₂ required = number of moles of MgCl₂ x molar mass
Molar mass of MgCl₂:
Atomic mass of Cl = 35.5g
Atomic mass of Mg = 24g
MgCl₂ = 24 + (35.5x2) = 95gmol⁻¹
Mass of MgCl₂ required = 1.14mole x 95gmole⁻¹ = 108.3g
Answer:
7,01 g of indole-3-acetic acid
Explanation:
The milimolar concentration (mM) is defined as the ratio of milimoles per Liter of solution. 400mM means 400mmoles / L that is the same of <em>0,4mol / L</em>
100mL are <em>0,1L</em>. Using these values:
0,1L × (0,4mol / L ) = 0,04moles of indole-3-acetic acid.
As the MW of the molecule is 175,2 g/mol:
0,04mol × (175,2g / mol) = <em>7,01 g of indole-3-acetic acid</em>
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Thus, <em>you need 7,01 g of indole-3-acetic acid to generate your solution</em>.
I hope it helps!
Answer:
B
Explanation:
The component carbon (C) has an nuclear number of 6, which suggests that all impartial carbon particles contain 6 protons and 6 electrons. In a commonplace test of carbon-containing fabric, 98.89% of the carbon particles too contain 6 neutrons, so each encompasses a mass number of 12.
Hope that helps
have a good day
Can i have brain too pls!!!
Answer:
V = 44.83 L
Explanation:
Given data:
Mass of fluorine = 76 g
Temperature = 0°C (0°C + 273 = 273 K)
Pressure = 101.3 Kpa ( 101.3 / 101 = 1 atm)
Volume of fluorine = ?
Solution:
Number of moles of F = Mass/ molar mass
Number of moles = 76 g/ 38 g/mol
Number of moles = 2 mol
Volume of fluorine:
PV = nRT
V = nRT/ P
V = 2 mol × 0.0821 atm. L/ mol. k × 273 k / 1 atm
V = 44.83 L. atm / 1 atm
V = 44.83 L
