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3 years ago

How to make slime with baking soda and no glue?

Chemistry

2 answers:

Dahasolnce [82]3 years ago

7 0

Measure out a cup of baking soda. Pour a cup (240 mL) of baking soda into a mixing bowl. ...

Mix green dish soap into your baking soda. Squirt a small amount of dish soap into your baking soda. ...

Add more baking soda if the solution gets runny. ...

Add a bit of food coloring if necessary. ...

Play with your slime.

alisha [4.7K]3 years ago

6 0

With dish soap baking soda and contact solution

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How do I balance this equation? ?KNO3 → ?K2O + ?N2(g)+ ?O2(g) and what type of reaction is it?

nirvana33 [79]

Answer:

4KNO3 ==> 2K2O + 2N2 + 5O2

Explanation:

It's a decomposition, but not a simple one.

KNO3 ==> K2O + N2 + O2 I don't usually do this, but I think the easiest way to proceed is to balancing the K and N together. That will require a 2 in front of KNO3

4KNO3 ==> 2K2O + 2N2 + 5O2

Now you have (3*4) = 12 oxygens. Two are on the K2O. So the other 10 must be on the O2

That should do it.

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3 years ago

Determine the mass of hydrogen contained in 9.06 x 1024 H2O molecules.

Elza [17]

Answer:

15.2 g H2

Explanation:

2H2O -> 2H2 + O2

9.06 x 10^24 molecules x (1 mol/6.022 x 10^23 molecules) x (2 mol H2/2 mol H2O) x (1.008 g/1 mol) = 15.2 g H2

4 0

3 years ago

Amphetamine (C9H13N) is a weak base with a pKb of 4.2.

QveST [7]

Weak base: [OH⁻] = √Kb.C

pKb = 4.2

$\tt Kb=10^{-4.2}$

c = concentration

MM Amphetamine (C9H13N) = 135.21 g/mol

c = 215 mg/L = (0.215 g : 135,21 g/mol) / L = 0.00159 mol/L = 1.59 x 10⁻³ mol/L

$\tt [OH^-]=\sqrt{10^{-4.2}\times 1.59\times 10^{-3}}=3.17\times 10^{-4}$

pOH = 4 - log 3.17

pH = 14 - (4 - log 3.17)

pH = 10 + log 3.17 = 10.50

4 0

2 years ago

Find the density if the volume is 15 mL and the mass is 8.6 g. (5 pts)

allsm [11]

Answer:

$\large \boxed{\text{0.57 g/mL; 3.7 mL; 6.6 g; 0.366 g/mL}}$

Explanation:

1. Density from mass and volume

$\text{Density} = \dfrac{\text{mass}}{\text{volume}}\\\\\rho = \dfrac{m}{V}\\\\\rho = \dfrac{\text{8.6 g}}{\text{15 mL}} = \text{0.57 g/mL}\\\text{The density is $\large \boxed{\textbf{0.57 g/mL}}$}$