Answer:
9.63 L.
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
So the consumed amounts of hydrochloric acid and bromine are the same to the beginning based on:
In such a way, the yielded moles of hydrobromic acid and chlorine are:
Thus, the volume of the sample, after the reaction is the same as no change in the total moles is evidenced, that is 9.63L.
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Answer: The coefficient in front of AgCl when the equation is properly balanced is 2.
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.
Decomposition of silver chloride is represented as:
Thus the coefficient in front of AgCl when the equation is properly balanced is 2.
The chemical formula C₂H₆O, which is designated as option D, is equivalent to this structural formula.
<h3><u>What is a Chemical Formula ?</u></h3>
Chemical element symbols, numbers, and occasionally additional symbols like parentheses, dashes, brackets, commas, and plus (+) and minus () signs are used in a chemical formula to represent information about the chemical proportions of the atoms that make up a certain chemical compound or molecule.
- An empirical formula represents by symbols, such as Na for sodium and Cl for chlorine, with subscripts that show the relative number of atoms in each.
- The composition of any member of an entire class of compounds can be represented by a general formula, a sort of empirical formula.
To know more about Chemical formulas, refer to:
brainly.com/question/26388921
<span>To calculate the number of moles of aluminum, sulfur, and oxygen atoms in 4.00 moles of aluminum sulfate, al2(so4)3. We will simply inspect the "number" of aluminum, sulfur, and oxygen atoms available per one mole of the compound. Here we have Al2(SO4)3, which means that for every mole of aluminum sulfate, there are 2 moles of aluminum, 3 (1 times 3) moles of sulfur, and 12 (4x3) moles of oxygen. Since we have four moles of Al2(SO4)3 given, we simply multiply 4 times the moles present per 1 mole of the compound. So we have 4x2 = 8 moles of Al, 4x3 = 12 moles of sulfur, and 4x12 = 48 moles of oxygen.
So the answer is:
8,12,48
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