Answer:
C. 
Step-by-step explanation:
Please find the attachment.
We have been given that secants AC and DB intersect at point E inside the circle. Given that the measure of arc 
, arc 
, and arc 
. We are asked to find the measure of angle AED.
We know that the measure of angle formed by two intersecting secants is half the sum of measure of the arcs by intercepted by the angle and its vertical angle.
Let us find measure of arc AD by subtracting measure of given arcs from 360 degrees as:
Therefore, measure of angle AED is 130 degrees and option C is the correct choice.
Answer:
Step-by-step explanation:
2
(
2
x
−
1
)
+
7
<
13
Expand LHS
→
4
x
−
2
+
7
<
13
4
x
+
5
<
13
4
x
<
13
−
5
4
x
<
8
Divide through by
4
→
x
<
2
x
<
2
is represented on the real line by the interval
(
−
∞
,
2
)
This can be represented on the
x
y
−
plane by the area to the left of the vertical line
x
=
2
as graph below.
graph{2(2x-1)+7<13 [-10, 10, -5, 5]}
Answer:
Step-by-step explanation:
56.27 =
50
+ 6
+ 0.2
+ 0.07
Expanded Factors Form:
56.27 =
5 × 10
+ 6 × 1
+ 2 × 0.1
+ 7 × 0.01
Expanded Exponential Form:
56.27 =
5 × 101
+ 6 × 100
+ 2 × 10-1
+ 7 × 10-2
Word Form:
56.27 =
fifty-six and twenty-seven hundredths
Answer:
The interquartile range is <em>50.</em>
Step-by-step explanation:
To find our answer we have to first <em>quartile 1</em> and <em>quartile 3</em> are equal too. When we look at the plot <em>quartile 1 </em>is equal to <em>20,</em> <em>quartile 3 </em>is equal to <em>70</em> because it is in between <em>60</em> and <em>80</em>. Now to find the interquartile range we will <em>subtract 70</em> from <em>20</em> and we get <em>50</em>. Therefore, <u><em>50</em></u><em> is our answer.</em>
