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mr_godi [17]
3 years ago
6

Which of the graphs below illustrates water boiling in Denver, Colorado? (Altitude 1,600 meters.)

Chemistry
1 answer:
lina2011 [118]3 years ago
4 0

Answer:

  • The graphs that come with this question are in the picture attached.

  • The answer is graph identified with the letter A.

Explanation:

The normal boiling point of water is 100°C. That is the temperature at which water boils when the atmospheric pressure is 1 atm, i.e. at sea level.

The liquids boil when its vapor pressure equals the atmospheric pressure; so the higher the atmospheric pressure the higher the boiling point, and the lower the atmospheric pressure the lower the boiling point.

Since, it is stated that the altitude of Denver, Colorado is 1,600 m, the atmosperic pressure (ther pressure exerted by the columnn of air above the place) is lower than 1 atm (atmospheric pressure at sea level).

Hence, water boiling point in Denver is lower than 100°C.

The graphs shown represent the temperature (T °C) as water is heated. Since when liquids boil their temperature remains constant during all the phase change, the flat portion of the graph represents the time during which the substance is boiling.

In the graph A, the flat portion is below 100°C; in the graph B, the flat portion is at 100 °C; in the graph C the flat part is above 100ªC, and, in graph D, there is not flat part. Then, the only graph that can illustrate water boiling in Denver, Colorado is the graph A.

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Which of these equations are correct? Select all that apply
nikitadnepr [17]

Answer:

The answer to your question is below

Explanation:

There are 4 laws of gases

- Charles

  \frac{V1}{T1} = \frac{V2}{T2}

- Gay Lussac

 \frac{P1}{T1} = \frac{P2}{T2}

- Boyle - Mariotte

 P1V1 = P2V2

- General law of gases

  \frac{P1V1}{T1} = \frac{P2V2}{T2}

Let's use these formulas to answer the question

p2 = V2/P1                  This is not a law of gases

p1= V1/k                        This formula is similar to Boyle mariotte equation

                                     but is not.

V2 = k/P2                      This equation is correct is Boyle Mariotte formula

V2 = P1V1/ P2               This equation is also correct is Boyle Mariotte formula

V1 = P1/P2 (V2)            This equation is incorrect

P2 = (P1) V1/V2             This equation is correct is Boyle mariotte formula

4 0
4 years ago
for each pair of compounds below , identify the one that would be expected to have more ionic character.explain you choice. (a)N
Tju [1.3M]

Answer:

a)NaBr

b)FCl

Explanation:

To identify which compound is more ionic we will calculate the electronegativity difference.

A) NaBr

Electronegativity of Na = 0.93

Electronegativity of Br = 2.96

Electronegativity difference = 2.96- 0.93 = 2.03

HBr

Electronegativity of H = 2.2

Electronegativity of Br = 2.96

Electronegativity difference = 2.96 - 2.2 = 0.76

NaBr have more ionic character because of large electronegativity difference.

B) BrCl

Electronegativity of Cl = 3.16

Electronegativity of Br = 2.96

Electronegativity difference = 3.16 - 2.96 = 0.2

FCl

Electronegativity of F = 3.98

Electronegativity of Br = 2.96

Electronegativity difference = 3.98 - 2.96 = 1.02

FCl have more ionic character because of large electronegativity difference.

8 0
3 years ago
if you are given the number of molecules in an undentified chemical compound, can you calculate the number of moles
krok68 [10]
Divide it by avagardo's constant that should work as its the number of particles. 

8 0
3 years ago
Zn(s)+2HCl(aq)= Zncl2(aq)+H2(g)
algol13
<span>There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. We calculate as follows:
</span>
2.5 M HCl = 2.5 mol HCl / L soln

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M1V1 = M2V2
18 M(V1) = 2.5 M(0.1224 L)
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4 0
4 years ago
What makes electrons jumo to other orbits around the nucleus then fall again?
Tamiku [17]

Answer:

The higher the excitation state, the more energy the electron contains. When an electron absorbs energy, it jumps to a higher orbital. ... An electron in an excited state can release energy and 'fall' to a lower state.

7 0
3 years ago
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