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3 years ago

20 points!!!

Mathematics

2 answers:

Ghella [55]3 years ago

8 0

Area of semi circle: you know the radius is 5. 5^2 * pi = 25pi/2 = 12.5pi
For triangle: bh/2 = (10 * 10)/2 = 50
Add them together: 12.5pi + 50
12.5pi = 39.25
39.25 + 50 = 89.25
It’s closest to D

Svetach [21]3 years ago

8 0

Area of equilateral triangle is =

$\sqrt{3} \div 4 \times s {}^{2}$

Root 3/4*10*10

Root 3/4*100

Root 3*25

25 root 3

Area of semicircle =1/2*22/7*5²

=1/2*22/7*25

(11*25)/7

275/7

=39.28

Adding areas of triangle and semicircle

25 root 3 +39.28

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Find the area of the figure <br><br> Someone help I’m giving 30 points

Stels [109]

Answer:

126.5 cm

Step-by-step explanation:

First, find the area of the rectangular shape at the bottom.(think of this as 2 separate shapes then add their areas together to find the final area)

11x8=88 cm

Next, find the area of the triangle.

Area of triangle = base x height /2

11x7=77

77/2=38.5

88+38.5=126.5 cm

7 0

3 years ago

I need help please asp !!!

Marina86 [1]

Answer:

They are all equal and identical in form; coinciding exactly when superimposed.

Step-by-step explanation:

4 0

3 years ago

The function f(x)=-10(x)(x-4) represents the approximate height of a projectile launch on the ground into the air as a function

ELEN [110]

Answer:

4 seconds.

Step-by-step explanation:

The function f(x)=-10(x)(x-4) ........ (1), represents the approximate height of a projectile launch on the ground into the air as a function of time in seconds x.

Now, we are asked that for how long from the launch does the projectile stays in the air.

Therefore, we have to solve the equation (1) making f(x) as zero.

Hence, 10x(x - 4) = 0

⇒ x = 0 or x = 4

(As x can not be zero since at x = 0 sec, the projectile was at the ground.}

Hence, x = 4 seconds.

Therefore, the projectile was in the air for 4 seconds. (Answer)

4 0

3 years ago

Read 2 more answers

A large car insurance company selected samples of single and married male policyholders and recorded the number who made an insu

nalin [4]

Answer:

The null hypothesis is rejected.

There is enough evidence to support the claim that rates are higher for single male policyholders verses married male policyholders (P-value = 0.004).

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that rates are higher for single male policyholders verses married male policyholders.

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0$

The significance level is 0.05.

The sample 1 (single group), of size n1=450 has a proportion of p1=0.1489.

$p_1=X_1/n_1=67/450=0.1489$

The sample 2 (married group), of size n2=925 has a proportion of p2=0.1005.

$p_2=X_2/n_2=93/925=0.1005$

The difference between proportions is (p1-p2)=0.0483.

$p_d=p_1-p_2=0.1489-0.1005=0.0483$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{67.005+93}{450+925}=\dfrac{160}{1375}=0.1164$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.1164*0.8836}{450}+\dfrac{0.1164*0.8836}{925}}\\\\\\s_{p1-p2}=\sqrt{0.0002+0.0001}=\sqrt{0.0003}=0.0184$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.0483-0}{0.0184}=\dfrac{0.0483}{0.0184}=2.62$

This test is a right-tailed test, so the P-value for this test is calculated as (using a z-table):

$P-value=P(z>2.62)=0.004$

As the P-value (0.004) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that rates are higher for single male policyholders verses married male policyholders.

6 0

4 years ago

Which table does NOT represent a function?

Anna35 [415]

D because some of the inputs have the same output therefor it is not a function

4 0

3 years ago

Read 2 more answers