Answer:
just use the tongs and put it on a plate
Explanation:
There are 19.5 g Na in 71.4 g NaHCO₃
Calculate the <em>molecular mass of NaHCO₃</em>.
1 Na = 1 × 22.99 u = 22.99 u
1 H = 1 × 1.008 u = 1.008 u
1 C = 1 × 12.01 u = 12.01 u
3 O = 3 × 16.00 u = <u>48.00 u
</u>
TOTAL = 84.008 u
So, there are 22.99 g of Na in 84.008 g NaHCO₃.
∴ Mass of Na = 71.4 g NaHCO₃ × (22.99 g Na/84.008 g NaHCO₃) = 19.5 g Na
Answer:
The mass of CH4 is 60, 29 grams.
Explanation:
We use the weight of the atoms C and H for calculate the molar mass:
Weight of CH4= weight C+ 4 x weight H= 12,01 g/mol +4 x 1,008g/mol=
Weight of CH4 =16, 042 g/mol
1molCH4-----16, 042grams
3,758 mol CH4--X= (3,758 mol CH4 x 16, 042 grams)/1 mol CH4=60,285836 grams
Physical properties can be observed or measured without changing the composition of matter. These are properties such as mass, weight, volume, and density. Remember that density is a physical property.
Answer:
pH + pOH = 14, [H₃0⁺] [0H⁻] = 10⁻¹⁴
Explanation:
When it comes to questions involving pH, the equations used are;
[H₃0⁺] [0H⁻] = 10⁻¹⁴
This equation shows the concentration of hydroxonium ions alongside that of the hydroxide ions.
pH + pOH = 14
If the value of either the pH of the pOH is know,one can calculate the value of the other using this equation.
