Find the missing angles m∠E= m∠F=
1 answer:
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Answer:
P'(-3, -8), Q'(-6, 4), R'(1, -1)
Step-by-step explanation:
When you reflect a point (x, y) across the x-axis, the x-coordinate remains the same, but the y-coordinate gets the opposite sign: it becomes (x, -y).
Thus, if a point P, say, (-3, 8) is eightn units above the x-axis, its reflection P' will be the same distance below, at (-3, -8).
Thus, we get the following transformations.
P (-3, 8) ⟶ P' (-3, -8)
Q (-6, -4) ⟶ Q' (-6, 4)
R (1, 1) ⟶ R' (1, -1)
Thus, the vertices of the reflected triangle are P' (-3, -8), Q' (-6, 4), R' (1, -1).
The image below shows ∆PQR and its reflection ∆P'Q'R' across the x-axis.
