This problem is describing a gas mixture whose mole fraction of hexane in nitrogen is 0.58 and which is being fed to a condenser at 75 °C and 3.0 atm, obtaining a product at 3.0 atm and 20 °C, so that the removed heat from the system is required.
In this case, it is recommended to write the enthalpy for each substance as follows:
Whereas the specific heat of liquid and gaseous n-hexane are about 200 J/(mol*K) and 160 J/(mol*K) respectively, its condensation enthalpy is 31.5 kJ/mol, boiling point is 69 °C and the specific heat of gaseous nitrogen is about 29.1 J/(mol*K) according to the NIST data tables and 
and 
are the mole fractions in the gaseous mixture. Next, we proceed to the calculation of both heat terms as shown below:
It is seen that the heat released by the nitrogen is neglectable in comparison to n-hexanes, however, a rigorous calculation is being presented. Then, we add the previously calculated enthalpies to compute the amount of heat that is removed by the condenser:
Finally we convert this result to kJ:
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Answer:
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Explanation:
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Answer:
Formed by adding 5 g of sugar to 1 L of water
Explanation:
The substance formed by adding 5 g of suagr to 1 L of water is a mixture.
<em>A mixture is defined as two or more substances that are physically mixed but do not react together. It thus means that the component substances of a mixture can be retrieved through appropriate means of separations.</em>
<u>A mixture of sugar and water can be separated by evaporation. The mixture is heated and the vapor from the boiling water can be condensed to retrieve the water while the residue will give the sugar that was initially dissolved in it. </u>
The products formed from other descriptions in the illustration cannot be separated ordinarily and thus, are not considered to be mixture. The components have been chemically combined together.
