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Mariana [72]
3 years ago
15

Complete and balance HBr(aq)+NaHCO3(aq)→

Chemistry
2 answers:
lara [203]3 years ago
5 0

Answer:

NaHCO3(aq) + HBr(aq) = CO2(g) + H2O(l) + NaBr(aq)

Explanation:

I think it's a doubel replacement.

ivolga24 [154]3 years ago
4 0

Answer:

Explanation:

S

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The equilibrium constant for the gas-phase isomerization of borneol (c10h17oh) to isoborneol at 503 k is 0.106. a mixture consis
Dimas [21]
The solution is as follows:

K = [Partial pressure of isoborneol]/[Partial pressure of borneol] = 0.106

The molar mass of isoborneol/borneol is 154.25 g/mol

Mol isoborneol = 15 g/154.25 = 0.0972 mol
Mol borneol = 7.5 g/154.25 = 0.0486 mol

Use the ICE approach

        borneol  →  isoborneol
I         0.0972           0.0486
C         -x                     +x
E     0.0972 - x        0.0486 + x

Total moles = 0.1458

Using Raoult's Law,
Partial Pressure = Mole fraction*Total Pressure
[Partial pressure of isoborneol] = [(0.0972-x)/0.1458]*P
[Partial pressure of borneol] = [(0.0486+x/0.1458)]*P

0.106 = [(0.0972-x)/0.1458]*P/ [(0.0486+x/0.1458)]*P
Solving for x,
x = 0.0832 

Thus,
<em>Mol fraction of borneol = (0.0486+0.0832)/0.1458 = 0.904</em>
<em>Mol fraction of isoborneol = (0.0972-0.0832)/0.1458 = 0.096</em>
6 0
3 years ago
The Ka for formic acid (HCO2H) is 1.8 × 10-4. What is the pH of a 0.35 M aqueous solution of sodium formate (NaHCO2)?
anzhelika [568]

Answer:

9.36

Explanation:

Sodium formate is the conjugate base of formic acid.

Also,

K_a\times K_b=K_w

K_b for sodium formate is K_b=\frac {K_w}{K_a}

Given that:

K_a of formic acid = 1.8\times 10^{-4}

And, K_w=10^{-14}

So,

K_b=\frac {10^{-14}}{1.8\times 10^{-4}}

K_b=5.5556\times 10^{-11}

Concentration = 0.35 M

HCOONa    ⇒     Na⁺ +    HCOO⁻

Consider the ICE take for the formate  ion as:

                                   HCOO⁻ + H₂O   ⇄   HCOOH + OH⁻

At t=0                              0.35                            -              -

At t =equilibrium           (0.35-x)                          x           x            

The expression for dissociation constant of sodium formate is:

K_{b}=\frac {[OH^-][HCOOH]}{[HCOO^-]}

5.5556\times 10^{-11}=\frac {x^2}{0.35-x}

Solving for x, we get:

x = 0.44×10⁻⁵  M

pOH = -log[OH⁻] = -log(0.44×10⁻⁵) = 4.64

pH + pOH = 14

So,

<u>pH = 14 - 4.64 = 9.36</u>

5 0
3 years ago
What do The seven dots around fluorine represent
borishaifa [10]
The seven dots around flourine are the valence electrons
7 0
3 years ago
Which statement is true regarding carbonic acid (H 2CO 3)? If body fluids are too alkaline, carbonic acid is excreted through th
dimaraw [331]

Answer:

the correct option is : If body fluids are too acidic, carbonic acid is excreted through the respiratory system in the form of carbon dioxide and water.

Explanation:

Metabolic acidosis is compensated by two systems, the renal and respiratory systems.

In the case of the respiratory system, the mechanism it uses to compensate for this phenomenon is to release the carbonic acid molecule dissociated into its components, that is, in the form of water and carbon dioxide.

The greater the acidosis, the more hyperventilation the person will have, and this is because they seek to eliminate carbonic acid more efficiently and quickly, along with renal excision.

The metabolic acidosis generated by carbonic acid is lethal, since the proteins in our body are denatured and the homeostasis of all systems is corrupted.

8 0
3 years ago
A student explained to the class that helium has 8 valence electrons because it is in group 18. Is the student correct?
lys-0071 [83]
<span>The student is incorrect because helium has 2 valence electrons and it's in group 18 because the first energy level is full. Although helium is placed in Group 18 which generally has 8 valence electrons, it does not have 8 valence electrons as the student suggested. It was grouped together with the noble gases because it exhibits similar properties with them. </span>
5 0
3 years ago
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