Answer:
Examine the units: If the density is 1 g/mL, how many mL do you need to make 250 g?
X mL * 1 g/mL = 250 g
Solve for X
x mL = 250 g / 1 g/mL = 250 mL
<em>Hope</em><em> this</em><em> helps</em><em> </em><em>:</em><em>)</em>
Missing data in your question: (please check the attached photo)
from this balanced equation:
M(OH)2(s) ↔ M2+(aq) + 2OH-(aq) and when we have Ksp = 2x10^-16
∴Ksp = [M2+][OH]^2
2x10^-16 = [M2+][OH]^2
a) SO at PH = 7 ∴POH = 14-PH = 14- 7 = 7
when POH = -㏒[OH]
7= -㏒[OH]
∴[OH] = 1x10^-7 m by substitution with this value in the Ksp formula,
∴[M2+] =Ksp /[OH]^2
= (2x10^-16)/(1x10^-7)^2
= 0.02 M
b) at PH =10when POH = 14- PH = 14-10 = 4
when POH = -㏒[OH-]
4 = -㏒[OH-]
∴[OH] = 1x10^-4 ,by substitution with this value in the Ksp formula
[M2+] = Ksp/ [OH]^2
= 2x10^-16 / (1x10^-4)^2
= 2x10^-8 Mc) at PH= 14
when POH = 14-PH
= 14 - 14
= 0
when POH = -㏒[OH]
0 = - ㏒[OH]
∴[OH] = 1 m
by substitution with this value in Ksp formula :
[M2+] = Ksp / [OH]^2
= (2x10^-16) / 1^2
= 2x10^-16 M
Based on distance to the nearest water well, the drilling site that would pose the least risk of methane contamination would be the one farthest away from the water well.
Methane is a gas that is known to escape from the ground and rise up into the atmosphere. If the drilling site is too close to the water well, there is a greater risk that the methane could contaminate the water.
The atmosphere is the air that surrounds us. It is a mixture of gases, including nitrogen, oxygen, and carbon dioxide. The atmosphere protects us from the Sun's ultraviolet radiation and from the cold of space. It also contains the Earth's weather, which is caused by the Sun's energy.
Learn more about Methane at : brainly.com/question/2127750
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I believe that what happens here is that when
those cells carrying those intercellular signals do no pass through the
connections, actually the signal is passed through or are transferred to adjacent
cells for signal transmission, hence the answer is:
<span>B</span>
Answer:
you mean KI? kI potassium K must be a uppercase.
Explanation:
<h2>CuSO4 + KI = CuI + I2 + K2SO4</h2>
Thats what happened.
CuI is insoluble is water.So Its a precipitation.I2 (iodine) is purple gas...
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