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Molodets [167]
3 years ago
8

As the solar system cooled and developed, larger bodies were pushed away from its center by gravity.

Physics
2 answers:
Ann [662]3 years ago
5 0
False, there isn’t gravity in space.
Darya [45]3 years ago
4 0

Answer:

True

Explanation:

The universe is widely spread so larger bodies were pushed from the universe’s center by gravity.

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The graph above shows the position x as a function of time for the center of mass of a system of particles of total mass 6. 0 kg
kumpel [21]

The resulting change in momentum of the system will be +18.6 Ns. The momentum is conserved.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

m is the mass =6.0 kg

t is the time interval=2 second

From Newton's second law;

\rm \triangle P =m \triangle V \\\\ \triangle P= m(\frac{\triangle x}{\triangle t} )\\\\

From the graph;

\rm \triangle t = 2sec\\\\ \triangle x = (12-8) m

The change in the momentum is;

\rm \triangle P = m\tr(\frac{v-u}{t}) \\\\ \triangle P =9.3 \times \frac{12-8}{2} \\\\ \triangle P= +18.6 \  N.s

Hence, the resulting change in momentum of the system will be +18.6 Ns.

To learn more about the law of conservation of momentum, refer;

brainly.com/question/1113396

#SPJ1

6 0
2 years ago
Solve the equation. 5x-5=10x+2
Veronika [31]

Answer:

x = - 1.4

Explanation:

-5=10x+2-5x     (subtract 5x from both sides)

-5=5x+2     (simplify)

-5-2=5x     (subtract 2 from both sides)

-7=5x      (simplify)

x=-7/5     (divide both sides by 5)

x=-1.4    (simplify)

i would really appreciate getting a brainliest. anyways i hope this helped and have a great rest of your day/night!! :)

8 0
4 years ago
Read 2 more answers
If the ball shown in the figure lands in 0.5 s, about what height was it thrown from?
Ede4ka [16]

Answer: 1.22 m

Explanation:

The equation of motion in this situation is:

y=y_{o}+V_{oy}t-\frac{g}{2}t^{2} (1)

Where:

y=0 is the final height of the ball

y_{o}=h is the initial height of the ball

V_{oy}=V_{o}sin(0\°)=0 is the vertical component of the initial velocity (assuming the ball was thrown vertically and there is no horizontal velocity)

t=0.5 s is the time at which the ball lands

g=9.8 m/s^{2} is the acceleration due gravity

So, with these conditions the equation is rewritten as:

h=\frac{g}{2}t^{2} (2)

h=\frac{9.8 m/s^{2}}{2}(0.5 s)^{2} (3)

Finally:

h=1.22 m

4 0
3 years ago
Physics HELP!
shusha [124]

Answer:

1. B

2. A

Explanation:

1. The displacement is the change in position.  At t = 0, x = 1.0.  At t = 8.0, x = 6.0.  So from t=0 to t=8, Δx = 6.0 − 1.0 = 5.0.

2. The instantaneous velocity is the slope of the tangent line at any point of a position vs. time graph.

The average velocity is the displacement divided by the time interval.

6 0
3 years ago
Please help with 4 and 5, thank you :)
allochka39001 [22]

Answer: #4

Sally is faster.

Explanation:

If you multiply Sallies it is going to be less than Jessica's.

6 0
3 years ago
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