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Agata [3.3K]
3 years ago
9

What percent of 24 is 18 set up a percent proportion and solve

Physics
2 answers:
vfiekz [6]3 years ago
6 0
Okie, I don't know what you want to "solve" for but I can help you find the percent of 24 in which is 18. So basically, you want to take the number that the question number (i dont know if that made sense) which is 18 essentially. And you divide it from the number that it is out of which is 24. Then multiply it by 100 to find the percent from the decimal. 
18 / 24 = .75 x 100 = 75 %
So, 18 is 75% of 24.
I hope this helps :-)
MrRissso [65]3 years ago
4 0

Answer:

75%

Explanation:

18/24=x/100

sorry for late answer i needed the points.

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Explanation:

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A drag racing car with a weight of 1600 lbf attains a speed of 270 mph in a quarter-mile race. Immediately after passing the tim
Kaylis [27]

Answer:

15.065ft

Explanation:

To solve this problem it is necessary to consider the aerodynamic concepts related to the Drag Force.

By definition the drag force is expressed as:

F_D = -\frac{1}{2}\rho V^2 C_d A

Where

\rho is the density of the flow

V = Velocity

C_d= Drag coefficient

A = Area

For a Car is defined the drag coefficient as 0.3, while the density of air in normal conditions is 1.21kg/m^3

For second Newton's Law the Force is also defined as,

F=ma=m\frac{dV}{dt}

Equating both equations we have:

m\frac{dV}{dt}=-\frac{1}{2}\rho V^2 C_d A

m(dV)=-\frac{1}{2}\rho C_d A (dt)

\frac{1}{V^2 }(dV)=-\frac{1}{2m}\rho C_d A (dt)

Integrating

\int \frac{1}{V^2 }(dV)= - \int\frac{1}{2m}\rho C_d A (dt)

-\frac{1}{V}\big|^{V_f}_{V_i}=\frac{1}{2m}(\rho)C_d (\pi r^2) \Delta t

Here,

V_f = 60mph = 26.82m/s

V_i = 120.7m/s

m= 1600lbf = 725.747Kg

\rho = 1.21 kg/m^3

C_d = 0.3

\Delta t=7s

Replacing:

\frac{-1}{26.82}+\frac{1}{120.7} = \frac{1}{2(725.747)}(1.21)(0.3)(\pi r^2) (7)

-0.029 = -5.4997r^2

r = 2.2963m

d= r*2 = 4.592m \approx 15.065ft

4 0
3 years ago
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Jobisdone [24]

Answer:

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