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steposvetlana [31]
3 years ago
13

My best friend just returned from the clinic. She just found out she is HIV- positive. She invited me for dinner. What should I

do? Should I go? What do I say to her and her family? Can I eat the foods she cooked or touched? Will she be all right? Imagine this letter is from a friend. Write a page response. Include reasons for your advice.
Physics
1 answer:
WITCHER [35]3 years ago
8 0

Answer:

yes, because you dont want to be mean and make her feel worse about it and hiv has something do with s3x not germs so yes go

Explanation:

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Amelia wanted to measure the mass of an object. Which SI unit should she use? A. kg B. amp C. mL D. K
yarga [219]
The answer of this question is
A.kg
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3 years ago
If a runner exerts 457 j of work to make 321 w of power then how long did it take the runner to do the work
MA_775_DIABLO [31]

The time taken by the runner to do the work is 1.42 seconds.

Given the data in the question;

  • Work done; W = 457J
  • Power; P = 321W
  • Time elapsed; t = \ ?

<h3>Power</h3>

Power can be simply referred to as the quantity of energy transferred per unit time.

It is expressed as;

P = \frac{W}{t}

Where W is work done and t is time elapsed.

To determine the time it took the runner to do the work, we substitute our given values into the expression above.

P = \frac{W}{t} \\\\t = \frac{W}{P} \\\\t = \frac{457J}{321W} \\\\t = \frac{457 kgm^2/s^2}{321 kgm^2/s^3}\\\\t = 1.42s

Therefore, the time taken by the runner to do the work is 1.42 seconds.

Learn more about Power and Work: brainly.com/question/2962104

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2 years ago
Airbags and safety belts can reduce injuries because they can
pashok25 [27]

Answer:

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5 0
3 years ago
A) A wire made from iron with a cross-section of diameter 0.800 mm carries a current of 14.0 A. Calculate the "areal current den
Veseljchak [2.6K]

Answer:

A) ρ=1.74x10^{26}

B) μ=1.68x10^{29}\frac{electron}{m^3}

C) v=1.03x10^{-3}\frac{m}{s}

D)e=8.99x10^-9

Explanation:

A)

The magnetic field can be find knowing the current is the charge per second

β= \frac{14eC*s}{1.6x10^{-19}C}\\

β= 8.75x10^{19}e*s

Electron density

ρ=\frac{8.75x10^{19}}{\pi*0.400x10^{-3}m} = 1.74x10^{26}

B)

μ= \frac{7.86}{56.2}\frac{g}{cm^3} \frac{mol}{g}*6.022x10^{23}\frac{molecules}{mol} *2 \frac{electron}{molecule}

μ=1.68x10^{23} \frac{electron}{cm^3}= 1.68x10^{29} \frac{electron}{m^3}

C)

The drift speed using last information found

v= \frac{J}{n*q} \\v= \frac{14A}{\pi*((0.40x10^-3)^2)*1.68x10^29*1.60x10^-19)} = 1.03x10^-3(\frac{m}{s} )

D)

To compared the random thermal motion and the current's drift speed

e=\frac{1.03x10^-3}{1.15x10^5} = 8.99x10^-9

8 0
3 years ago
Mr. Tolman believes that our universe is expanding, but with all of the gravitational force from the celestial bodies of space,
sattari [20]
The correct answer is A I believe but I may not be correct. Either A or B
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