My best friend just returned from the clinic. She just found out she is HIV- positive. She invited me for dinner. What should I
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Answer:
The potential difference between points A and B is 278.95 volts.
The potential difference between points B and C is -642.10 volts.
The potential difference between points A and C is -363.15 volts.
Explanation:
Given :
Charge of the particle, q = 19 nC = 19 x 10⁻⁹ C
Work is done to move a charge from point A to B, W₁ = 5.3 μJ
Work done to move a charge from point B to C, W₂ = -12.2 μJ
Let V₁ be the potential difference between point A and B, V₂ be the potential difference between point B and C and V₃ be the potential difference between point A and C.
The relation between work done and potential difference is:
W = qV
V = W/q ....(1)
Using equation (1), the potential difference between points A and B is:
Substitute the suitable values in the above equation.
V₁ = 278.95 V
Using equation (1), the potential difference between points B and C is:
Substitute the suitable values in the above equation.
V₂ = -642.10 V
The potential difference between points A and C is:
V₃ = V₁ + V₂
V₃ = 278.95 - 642.10
V₃ = -363.15 V
Answer:
Given:
Radius of ball bearing (r) = 1.5 mm = 0.15 cm
Density of iron (ρ) = 7.85 g/cm³
Density of glycerine (σ) = 1.25 g/cm³
Terminal velocity (v) = 2.25 cm/s
Acceleration due to gravity (g) = 980.6 cm/s²
To Find:
Viscosity of glycerine ()
Explanation:
Substituting values of r, ρ, σ, v & g in the equation: