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3 years ago

Pls do question 1 part d). tysm

Physics

1 answer:

Aneli [31]3 years ago

5 0

Answer:

Explanation:

cuz its informing the length of 5 and weight on 20N

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Two blocks of masses m and 3m are placed on a frictionless, horizontal surface. A light spring is attached to the more massive b

ivanzaharov [21]

Answer:

Explanation:

a ) Conservation of momentum is followed

m₁ v₁ = m₂ v₂

3m x 2 = m v

v = 6 m/s

Total kinetic energy

= 1/2 x .35 x 6 ² + 1/2 x 1.05 x 2 ²

= 8.4 J

This energy must be stored as elastic energy in the spring which was released as kinetic energy on burning the cord.

Yes , the conservation of momentum will be followed in the bursting apart process. Only internal forces have been involved in the process. Two equal and opposite internal forces are created by spring which creates motion and generates kinetic energy.

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3 years ago

A polar bear runs at a speed of 11 m/s and has a mass of 380.2 kg. How much Kinetic energy does the bear have?

Yanka [14]

Answer:

$\boxed{\sf Kinetic \ energy \ of \ the \ bear (KE) = 23002.1 \ J}$

Given:

Mass of the polar bear (m) = 6.8 kg

Speed of the polar bear (v) = 5.0 m/s

To Find:

Kinetic energy of the polar bear (KE)

Explanation:

Formula:

$\boxed{ \bold{\sf KE = \frac{1}{2} m {v}^{2} }}$

Substituting values of m & v in the equation:

$\sf \implies KE = \frac{1}{2} \times 380.2 \times {11}^{2}$

$\sf \implies KE = \frac{1}{ \cancel{2}} \times \cancel{2} \times 190.1 \times 121$

$\sf \implies KE = 190.1 \times 121$

$\sf \implies KE = 23002.1 \: J$

$\therefore$

Kinetic energy of the polar bear (KE) = 23002.1 J

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3 years ago

What are some guidelines for using self-assessments?

lakkis [162]

Decide which components you wish to assess yourself. There is no set order in which you do this. you could, for an example assess one or two elements and skip the rest.

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3 years ago

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Fine grains of beach sand are assumed to be spheres of radius 49.8 µm. these grains are made of silicon dioxide which has a dens

PIT_PIT [208]

Answer: $1.3\times10^{-9}kg$