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faltersainse [42]
3 years ago
14

Please guys help me i will help u too ​

Physics
2 answers:
Vika [28.1K]3 years ago
7 0
<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u></h2>

<u>G</u><u>i</u><u>v</u><u>e</u><u>n</u>

  • u = 20 m/s
  • v = 30 m/s
  • t = 10 s

<u>F</u><u>i</u><u>n</u><u>d</u><u> </u>

  • a = ?

<h2><u>E</u><u>x</u><u>p</u><u>l</u><u>a</u><u>n</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u></h2>

<u>U</u><u>s</u><u>i</u><u>n</u><u>g</u><u> </u><u>F</u><u>o</u><u>r</u><u>m</u><u>u</u><u>l</u><u>a</u>

★ v = u + at.

<u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>a</u><u>l</u><u>l</u><u> </u><u>v</u><u>a</u><u>l</u><u>u</u><u>e</u><u>s</u><u>.</u>

➡ 30 = 20 + a × 10

➡10a = 30 - 20

➡a = 10/10

➡a = 1 m/s².

matrenka [14]3 years ago
3 0

Answer:

calculate the cars acceleration usingv=u+at

Explanation:

m/s. After 5 s the car reaches the bottome of the hill. Its speed at the bottom of the ... accelerating left a rownie. 10. A cart slows down while moving away from the ... does it need to accelerate to a velocity of 20 m/s

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Answer:

A)\Phi=83.84\times 10^{-9}

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  • area of the coil, a=13.1 \times 10^{-4}\,m^2
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(A)

Initially the coil area is perpendicular to the magnetic field.

So, magnetic flux is given as:

\Phi=B.a\,cos \theta..................................(1)

\theta is the angle between the area vector and the magnetic field lines. Area vector is always perpendicular to the area given. In this case area vector is parallel to the magnetic field.

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\Phi=6.4\times 10^{-5}\times 13.1 \times 10^{-4}\, cos 90^{\circ}

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According to the Faraday's Law we have:

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