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3 years ago

Please guys help me i will help u too

Physics

2 answers:

Vika [28.1K]3 years ago

7 0

<h2>Solution</h2>

Given

u = 20 m/s
v = 30 m/s
t = 10 s

Find 

a = ?

<h2>Explanation</h2>

Using Formula

★ v = u + at.

Keep all values.

➡ 30 = 20 + a × 10

➡10a = 30 - 20

➡a = 10/10

➡a = 1 m/s².

matrenka [14]3 years ago

3 0

Answer:

calculate the cars acceleration usingv=u+at

Explanation:

m/s. After 5 s the car reaches the bottome of the hill. Its speed at the bottom of the ... accelerating left a rownie. 10. A cart slows down while moving away from the ... does it need to accelerate to a velocity of 20 m/s

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The solid rod shown has a radius of 0.75 in. if it is subjected to the force the 500lb determine the max normal stress developed

Kipish [7]

The normal stress follows the formula written below:

σ = F/A

There are two types of stress, axial and tangential. Since we are only given with the dimension of the radius (and not the length), the possible stress is axial. So, the area is,

A = πr² = π(0.75 in)² = 1.767 in²

So,
σ = F/A = 500 lb/1.767 in² = 282.94 psi

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3 years ago

. Inside a laser apparatus, the stimulation and relaxation of electrons in atoms causes many photons with the same to be continu

mrs_skeptik [129]

Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same wavelength to be continuously emitted.

From the questions given, the main objective is to fill in the gaps and add important information where necessary. The missing information is highlighted in bold and underlined.

Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same wavelength to be continuously emitted.

2. When these photons are emitted, they travel between two reflective

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3. This wave is the summation of all the photons being introduced with

every oscillation, and as they continue to travel, the amplitude

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4. This occurs because the photons are emitted in a coherent fashion;

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5. In a laser device, a small portion of photons are permitted to escape

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6. The generation of multiple wavelengths is possible in some laser

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2 years ago

Grade 11 physical science experiments on newtons second law experience

Nutka1998 [239]

Answer:

Newton's Second Law of Motion says that acceleration (gaining speed) happens when a force acts on a mass . Riding your bicycle is a good example of this law of motion at work. Your bicycle is the mass. Your leg muscles pushing pushing on the pedals of your bicycle is the force.

Explanation:

8 0

3 years ago

Ask Your Teacher Two long, straight wires are parallel and 11 cm apart. One carries a current of 2.9 A, the other a current of 5

dsp73

Answer:

The magnitude of force per unit length of one wire on the other is $2.7945\times 10^{-5}\ N$ and the direction is away from one another

The magnitude of force per unit length of one wire on the other is $2.7945\times 10^{-5}\ N$ and the direction is towards each other.

Explanation:

$\mu_0$ = Vacuum permeability = $4\pi\times 10^{-7}\ N/A^2$

$i_1$ = Current in first wire = 2.9 A

$i_2$ = Current in second wire = 5.3 A

r = Gap between the wires = 11 cm

Force per unit length

$F_{12}=F_{21}=\frac{\mu_0 i_1i_2}{2\pi r}\\ =\frac{4\pi\times 10^{-7}\times 2.9\times 5.3}{2\pi 0.11}\\ =2.7945\times 10^{-5}\ N$

The magnitude of force per unit length of one wire on the other is $2.7945\times 10^{-5}\ N$ and the direction is away from one another

$F_{12}=F_{21}=\frac{\mu_0 i_1i_2}{2\pi r}\\ =\frac{4\pi\times 10^{-7}\times 2.9\times 5.3}{2\pi 0.11}\\ =2.7945\times 10^{-5}\ N$

The magnitude of force per unit length of one wire on the other is $2.7945\times 10^{-5}\ N$ and the direction is towards each other.

7 0

3 years ago

An airplane is flying 340 km/hr at 12o east of north. the wind is blowing 40 km/hr at 34o south of east. what is the plane's act

seropon [69]

Define an x-y coordinate system such that
The positive x-axis = the eastern direction, with unit vector $\hat{i}$ .
The positive y-axis = the northern direction, with unit vector $\hat{j}$ .

The airplane flies at 340 km/h at 12° east of north. Its velocity vector is
$\vec{v}_{1} = 340(sin(15^{o})\hat{i} + cos(15^{o})\hat{j} ) = 88\hat{i} + 328.4\hat{j}$

The wind blows at 40 km/h in the direction 34° south of east. Its velocity vector is
$\vec{v}_{2} =40(cos(34^{o})\hat{i} - sin(24^{o})]\hat{j}) = 33.1615\hat{i} -22.3677\hat{j})$

The plane's actual velocity is the vector sum of the two velocities. It is
$\vec{v}=\vec{v}_{1}+\vec{v}_{2} = 121.1615\hat{i}+306.0473\hat{j}$

The magnitude of the actual velocity is
v = √(121.1615² + 306.0473²) = 329.158 km/h

The angle that the velocity makes north of east is
tan⁻¹ (306.04733/121.1615) = 21.6°

Answer:
The actual velocity is 329.2 km/h at 21.6° north of east.

8 0

3 years ago

Please guys help me i will help u too ​

Please guys help me i will help u too