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Nonamiya [84]
3 years ago
11

Dos Autos se acercan uno hacia el otro como se muestra en la figura. Si los carros chocan y quedan pegados, DETERMINE: a) las co

mponentes de la velocidad
después del choque.
b) La velocidad resultante después del choque,
c) El ángulo θ
Physics
1 answer:
lisov135 [29]3 years ago
8 0

Answer:

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Explanation:

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maxonik [38]

probabilityAnswer:

2/27

Explanation:

The elk can not be eaten so we remove that from the probablity

so we have x/18

songbird = 4/18

mice = 6/18

4/18*6/18 = 2/27

5 0
2 years ago
How does an atom of chlorine-37 become a chloride ion with a -1 charge?
kirill115 [55]

Answer:

B. The atom gains 1 electron, to make a total of 18 electrons.

Explanation:

Chlorine is the 17th element in the periodic table, so it has atomic number 17:

Z = 17

This means that a neutral atom of chlorine has 17 protons and 17 electrons.

When a chlorine atom gains 1 electron, its electric charge (initially zero) becomes -1, since the electron has negative charge of -1 (in elemntary charge units). This also means that the number of electrons in the ion is now

17 + 1 = 18

So the correct answer is

B. The atom gains 1 electron, to make a total of 18 electrons

5 0
3 years ago
Can enter through any cavity lined with mucus membranes
Gre4nikov [31]

Answer:

mucus

Explanation:

7 0
3 years ago
Atoms are made up of even smaller particles called ?
labwork [276]

Answer:

Atoms are made up of even smaller particles called <u>protons,</u><u> </u><u>electrons </u><u>&</u><u> </u><u>neutrons</u><u> </u><u>(</u><u>sub</u><u>-</u><u>atomic </u><u>particles)</u>

3 0
3 years ago
Read 2 more answers
An electron is released from rest at the negative plate of a parallel plate capacitor. The charge per unit area on each plate is
dmitriy555 [2]

Answer:

v = 1.15*10^{7} m/s

Explanation:

given data:

charge/ unit area= \sigma = 1.99*10^{-7} C/m^2

plate seperation = 1.69*10^{-2} m

we know that

electric field btwn the plates isE = \frac{\sigma}{\epsilon}

force acting on charge is F = q E

Work done by charge q id\Delta X =\frac{ q\sigma \Delta x}{\epsilon}

this work done is converted into kinectic enerrgy

\frac{1}{2}mv^2 =\frac{ q\sigma \Delta x}{\epsilon}

solving for v

v = \sqrt{\frac{2q\Delta x}{\epsilon m}

\epsilon = 8.85*10^{-12} Nm2/C2

v = \sqrt{\frac{2 1.6*10^{-19}1.99*10^{-7}*1.69*10^{-2}}{8.85*10^{-12} *9.1*10^{-31}}

v = 1.15*10^{7} m/s

8 0
3 years ago
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