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Nonamiya [84]
3 years ago
11

Dos Autos se acercan uno hacia el otro como se muestra en la figura. Si los carros chocan y quedan pegados, DETERMINE: a) las co

mponentes de la velocidad
después del choque.
b) La velocidad resultante después del choque,
c) El ángulo θ
Physics
1 answer:
lisov135 [29]3 years ago
8 0

Answer:

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Explanation:

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A person swims to the other end of a 20m long pool and back. What is their displacement?
mafiozo [28]

Answer:

Zero

Explanation:

It is given that,

A person swims to the other end of a 20m long pool and back.

We need to find his displacement.

Displacement = shortest path covered

He reaches at the same position as from where he has started. It means the shortest path covered is equal to 0 i.e. his displacement is zero.

3 0
3 years ago
Why is Carbon Tetrahydride a covalent bond? plzzz helpppp!!!!!!​
arlik [135]

Answer:

carbon has four unpaired electrons in its valence shell . hydrogen having one unpaired electron in its valence shell comes to bond with carbon by sharing a pair of electrons .since carbon needs 4 electrons to be stable, 4 hydrogen atoms take part in the bond . It's a covalent bond because the difference between the electronegativity of carbon and hydrogen is quite small .

7 0
3 years ago
How does a mathematical model help you understand the science concepts? Give an example.
sveta [45]
Usually describes a system by a set of variables in a set of equations established relationships between the variables and variables maybe of many types real or integer numbers Boolean values of strings for example
4 0
3 years ago
A train is 240 meters long and travels 20 m/s. How long does
const2013 [10]

Answer:

=18 sec

Explanation:

240m=20m/s, find 360m

360×20÷240=30m/s

time=distance÷speed

240÷20=12sec

if 240=12sec,find 360

360×12÷240

=18 sec

6 0
3 years ago
Assume the average value of the vertical component of Earth's magnetic field is 42 μT (downward) in some region that has an area
Oliga [24]

Answer:

The net magnetic flux through the rest of Earth's surface is  5.782\times10^{-2}\ T

Explanation:

Given that,

Magnetic field = 42 μT

Area A=3.71\times10^{5}\ km^2

A=3.71\times10^{11}\ m^2

We need to calculate the flux per unit area

flux\ per\ unit\ area=\dfrac{42\times10^{-6}}{3.71\times10^{11}}

flux\ per\ unit\ area=1.132\times10^{-16}\ T/m^2

We need to calculate the total earth's surface area

A'=4\pi r^2

A'=4\times\pi\times(6.3781\times10^{6})^2

A'=5.1120\times10^{14}\ m^2

We need to calculate the rest of earth's area

A''=A-A'

Put the value into the formula

A''=5.1120\times10^{14}-3.71\times10^{11}

A''=5.10829\times10^{14}\ m^2

We need to calculate the net magnetic flux through the rest of Earth's surface

B'=5.10829\times10^{14}\times1.132\times10^{-16}

B'=5.782\times10^{-2}\ T

Hence, The net magnetic flux through the rest of Earth's surface is  5.782\times10^{-2}\ T

3 0
4 years ago
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