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2 years ago

9

describe the behavior of the molecules in a liquid. Explain this behavior in terms of intermolecular forces.

1 answer:

tigry1 [53]2 years ago

5 0

Answer:

Molecules in liquids are held to other molecules by intermolecular interactions, which are weaker than the intramolecular interactions that hold the atoms together within molecules and polyatomic ions.

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How are sound waves different from the waves in the sea or the ripples on water???

nirvana33 [79]

Answer:

water wave shake energy over the surface to the sea, while sound waves thump energy trough the body of the air. sound waves are compression waves

<em>Hope</em><em> this</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>

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3 years ago

Which of these elements has the smallest atomic radius?

shutvik [7]

Answer:

Its Br on Ap ex

Explanation:

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3 years ago

The volume of a given mass of an ideal gas at constant pressure is

zmey [24]

Answer:

inversely proportional to the kelvin temperature

Explanation:

PV=nRT

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2 years ago

Read 2 more answers

11cm+11.38cm+500.55cm=

Vika [28.1K]

Answer:522.93 centimeters

Explanation:

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3 years ago

Two moles of an ideal gas are placed in a container whose volume is 2.3 x 10^-3 m3. The absolute pressure of the gas is 6.9 x 10

PtichkaEL [24]

Answer:

$K.E.=1.97\times 10^{-21}\ J$

Explanation:

Given that:-

Pressure = $6.9\times 10^5\ Pa$

The expression for the conversion of pressure in Pascal to pressure in atm is shown below:

P (Pa) = $\frac {1}{101325}$ P (atm)

Given the value of pressure = 43,836 Pa

So,

$6.9\times 10^5\ Pa$ = $\frac{6.9\times 10^5}{101325}$ atm

Pressure = 6.80977 atm

Volume = $2.3\times 10^{-3}\ m^3$ = 2.3 L ( 1 m³ = 1000 L)

n = 2 mol

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

6.80977 atm × 2.3 L = 2 mol × 0.0821 L.atm/K.mol × T

⇒T = 95.39 K

The expression for the kinetic energy is:-

$K.E.=\frac{3}{2}\times K\times T$

k is Boltzmann's constant = $1.38\times 10^{-23}\ J/K$

T is the temperature

So, $K.E.=\frac{3}{2}\times 1.38\times 10^{-23}\times 95.39\ J$

$K.E.=1.97\times 10^{-21}\ J$

3 0

3 years ago