Remeber:
Kinectic energy = [1/2]mv^2
Potential energy = m.g[h - h0]
6. When the snowboarder is still at the top, she does not have kinetic energy, given that the speed is zero.
There, at the top, the potential energy is maximum, given that the height, h - h0, is the highest.
So, ar the topo she only has potential energy.
7. From that point, the snowboarder, starts to gain velocity; is has started a process of conversion of potential energy to kinetic energy. More velocity, less height, more kinetic ener energy and less ptential energy.
At the very bottom, when she has reached the heigth of reference, h0, the term [h - h0] becomes zero, then the potential energy has dissapeared and all the energy has been transformed into kinetic energy; the speed and the kinetic energy are maximum.
Answer:
20.76 L OF CO2 WILL BE PRODUCED BY 45 G OF METHANE.
Explanation:
Equation of the reaction:
CH4 + 02 --------> CO2 + 2H20
Molar mass of methane = ( 12+ 1*4) g/mol = 16 g/mol
Calculate the number of moles present in 45 g of methane
1 mole of methane = 16 g / mol of methane
(45 / 16) mole of methane = 45 g of methane
= 2.8125 moles
Using the ideal gas equation:
PV = nRT
P = 1 atm
n = 2.812 moles
T = 90 C
R = 0.082 L atm/ mol C
V = unknown
So we have:
V = nRT / P
V = 2.8125 * 0.082 * 90 / 1
V = 20.756 L
In the production of CO2 by 45 g of methane, 20.756 L of methane was used.
Then, the volume of CO2 produced by this volume will be 20.756 L since 1 mole of methane produces 1 mole of CO2.
In other words;
1 mole of CH4 = 1 mole of CO2
22.4 dm3 of CH4 = 22.4 dm3 of CO2
20.76 DM3 = 20.76 dm3
The volume of CO2 produced will therefore be 20.76 L
