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3 years ago

How are concentration and chemical reaction rate related?

Chemistry

1 answer:

dem82 [27]3 years ago

7 0

Answer:

When the concentration of all the reactants increases, more molecules or ions interact to form new compounds, and the rate of reaction increases. When the concentration of a reactant decreases, there are fewer of that molecule or ion present, and the rate of reaction decreases.

Explanation:

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2KCIO3 -- 2KCL+3o2 is a balanced equation

Veronika [31]

Answer:

a) Balanced equation:

An equation is called balanced if there are same number and same type of atom on both sides of the equation.

b)Reason:

2KClO3--------2KCl + 3O2

Consider this equation in the reactants there are 2KClO3 and in the product there are 2KCl+3O2 . So reactants =products which is a case of balanced chemical equation .

Explanation:

4 0

3 years ago

A 34.57 mL sample of an unknown phosphoric acid solution is titrated with a 0.127 M sodium hydroxide solution. The equivalence p

Bas_tet [7]

Answer: The concentration of unknown phosphoric acid solution is 0.034 M

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_3PO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?M\\V_1=34.57mL\\n_2=1\\M_2=0.127M\\V_2=28.2mL$

Putting values in above equation, we get:

$3\times M_1\times 34.57=1\times 0.127\times 28.2\\\\M_1=\frac{1\times 0.127\times 28.2}{3\times 34.57}=0.034M$

Hence, the concentration of unknown phosphoric acid solution is 0.034 M

7 0

3 years ago

The ph of a 0.15 m aqueous solution of naz (the sodium salt of hz) is 10.7. what is the ka for hz?

andrew-mc [135]

Answer:
NaZ + H2O <----> HZ + OH-
[OH-] = [HZ]
[NaZ] = 0.15 M
pH = 10.7, so the pOH = 14-10.7 = 3.3; [OH-] = 10^-3.3 = 5.01E-4
kb = [OH-][HZ]/[NaZ] = (5.01E-4)^2/0.15 = 1.67E-6
ka = kw/kb = 1E-14/1.67E-6 = 5.99E-9 = 6.0E-9

5 0

3 years ago

Calculate the [H3O'J in a solution that has a pH of 9.11. A) 7.8 x 10-10 B) 1.3 x 10-5 C) 9.1 x 10-9 D) 0.96 E) 0.69

puteri [66]

Answer: The correct answer is Option A.

Explanation:

pH is defined as negative logarithm of hydronium ion concentration. It is basically defined as the power of hydrogen ions that are present in a solution.

Mathematically,

$pH=-\log[H_3O^+]$

pH of the solution = 9.11

Putting values in above equation, we get:

$9.11=-\log[H_3O^+]$

$[H_3O^+]=antilog(-9.11)$

$[H_3O^+]=7.8\times 10^{-10}$

Hence, the correct answer is Option A.

7 0

4 years ago

When the mineral dolomite (caco3·mgco3) is heated, it gives off carbon dioxide and forms a mixture of a metal oxide and a metal

luda_lava [24]

$MgCO_3.CaCO_3 ----\ \textgreater \ Heat---\ \textgreater \ CO_2 + MgO + CaCO_3$

Now, question is why MgO but not CaO.

At a dissociation pressure of 1 atm, the temperature at which CO2 and metal oxide is formed is :

For MgCO3 = 540 °C
For CaCO3 = 900 °C”
Also,
The driving force is the larger lattice energy of MgO(3795) vs that of CaO(3414 kJ mol^-1) . More the lattice energy, the more chances of that compound to form.
So MgO is formed first.

Carbonate is Calcium carbonate

6 0

4 years ago