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Julli [10]
3 years ago
6

38 POINTS - PEER COUNSELING 2 QUESTION

Chemistry
2 answers:
brilliants [131]3 years ago
7 0

anything except for a and d

Hoochie [10]3 years ago
6 0

C) You confronting her about the problem at hand.

<u>C) Amanda, why do you say mean things about me?</u>

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The invisible force that surrounds a magnet is called the ________
Sladkaya [172]
Magnetic field
happy to help
8 0
3 years ago
Question 1
podryga [215]

actually it is 5% of 100 is 5

Therefore, 5% of 500 is 5 x 5 = 25g

6 0
3 years ago
When the equation Fe +Cl2 FeCl3 → is balanced, what isthe coefficient for Cl2?
mixas84 [53]

Answer: Option (c) is the correct answer.

Explanation:

The given reaction is as follows.

    Fe + Cl_{2} \rightarrow FeCl_{3}

Number of atoms on reactant side are as follows.

  • Fe = 1
  • Cl = 2

Number of atoms on product side are as follows.

  • Fe = 1
  • Cl = 3

To balance the given equation, we multiply Fe by 2 and Cl_{2} by 3 on the reactant side. Therefore, the balanced chemical equation will be as follows.

           2Fe + 3Cl_{2} \rightarrow FeCl_{3}

Thus, the coefficient of Cl_{2} is 3.

7 0
4 years ago
Read 2 more answers
Given the unbalanced equation below, answer the following: Calculate the number of liters of 3.00 M lead (II) iodide solution pr
mr_godi [17]

The number of liters of 3.00 M lead (II) iodide : 0.277 L

<h3>Further explanation</h3>

Reaction(balanced)

Pb(NO₃)₂(aq) + 2KI(aq) → 2KNO₃(aq) + PbI₂(s)

moles of KI = 1.66

From the equation, mol ratio of KI : PbI₂ = 2 : 1, so mol PbI₂ :

\tt \dfrac{1}{2}\times 1.66=0.83

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large \boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So the number of liters(V) of 3.00 M lead (II) iodide-PbI₂ (n=0.83, M=3):

\tt V=\dfrac{n}{M}\\\\V=\dfrac{0.83}{3}\\\\V=0.277~L

5 0
3 years ago
Name some animals and plants that live on land?<br><br><br>please mark as brainliest​
beks73 [17]

Answer:

cats, ants, spiders, elephants, porcupine, tiger, kangaroo, and ostrich. Mosses, hornworts, liverworts, lycophyte, seed plants, pteridophytes, and archaeopteridales.

Explanation:

6 0
3 years ago
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