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TEA [102]
3 years ago
10

State and explain the three laws of chemical combination​

Chemistry
1 answer:
Elden [556K]3 years ago
5 0

Answer:

  • law of conservation of mass
  • law of definite proportion
  • Avogadro's law

Explanation:

Law of conservation of mass ⇒ it states that matter can neither be created or destroyed.In a reaction the energy and the mass remain constant

Law of definite proportion ⇒ it states that samples of compounds will always contain the same proportion of elements by mass.proportion of elements by weight will always remain the same;meaning that percent by weight in elements will remain the same regardless of origin and quantity

Avogadro's law ⇒ it sates that under the same conditions of pressure and temperature, equal volumes of all gases contain the same number of molecules.if there is 500 ml of carbon and oxygen, they will have the same molecules if exposed to the same pressure and teprature level

                   Hope this helps,and if it helps mark as branliest thx

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Hitman42 [59]

The answer is:

the molarity = 50 moles/liters

The explanation:

when the molarity is = the number of moles / volume per liters.

and when the number of moles =2.5 moles

and the volume per liters = 0.05 L

so by substitution:

the molarity = 2.5moles/0.05L

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7 0
2 years ago
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GrogVix [38]

Answer : The mole fraction of NaCl in a mixture is, 0.360

Explanation : Given,

Moles of NaCl = 7.21 mole

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\text{Mole fraction of }NaCl=\frac{\text{Moles of }NaCl}{\text{Moles of }NaCl+\text{Moles of }KCl+\text{Moles of }LiCl}

Now put all the given values in this formula, we get:

\text{Mole fraction of }NaCl=\frac{7.21}{7.21+9.37+3.42}=0.360

Therefore, the mole fraction of NaCl in a mixture is, 0.360

3 0
3 years ago
Find the number of CoCl2 units present in a 0.78 mol sample.
stich3 [128]

\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

1 mole of \sf{ COCl_2} has 6.022 × 10²³ molecules of the given compound.

So, 0.78 mole of \sf{COCl_2} will have ~

\qquad \sf  \dashrightarrow \: 0.78 \times 6.022 \times 10 {}^{23}

\qquad \sf  \dashrightarrow \:  \approx4.7 \times 10 {}^{23}  \:  \:  \: molecules

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