Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
Learn more about trigonometry here : brainly.com/question/7331447
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Answer:
254 4/7 or 254.34 ft² (it depends on which method you use.)
Step-by-step explanation:
To find the area of a circle, the formula is πr².
I'll use both 22/7 and 3.14 as pi, so I'll end up with two different answers. Just choose the more reliable one.
22/7 version:
22/7 * 9^2
22/7 * 81/1
1782/7
254 4/7 ft²
3.14 version:
3.14 * 9^2
3.14 * 81
314 - (3.14 * 19)
314 - 62.8 + 3.14
251.2 + 3.14
254.34 ft²
As I said, I ended up with two different answers. You also had said not to round my answer, so the 22/7 version has a mixed number.
Answer: The line starts at 1 positive, then from there go -4 (so go to the left) then 1 down from that point.
Step-by-step explanation: the problem is supposed to have been Y= -4/1 +1
The answer is 2x-6y=-14 is the aswer
